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Dima020 [189]
2 years ago
6

How many moles are in 25 g KMnO4

Chemistry
1 answer:
Ronch [10]2 years ago
8 0

Answer:

0.158 moles KMnO4

Explanation:

According to the Periodic Table,

K = 39.10 g/mol

Mn = 54.94 g/mol

O = 16.00 g/mol

KMnO4 = 39.10 g/mol + 54.94 g/mol + 4(16.00 g/mol) = 158.04 g/mol

25.0 grams KMnO4              1 mole

-----------------------------  x --------------------------  = 0.158 moles KMnO4

                                          158.04 grams

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Name the following FBr. ?
gogolik [260]

Answer:

FBr is a chemical formula representing "flourine monobromide."

Explanation:

Of course, FBR could represent a number of things, from the Federal Board of Revenue to a fluidized bed reactor. I gave the answer I did because you listed this question as Chemisty.

4 0
3 years ago
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4 0
2 years ago
How many moles are present in a 5.8 g sample of copper?
Oksanka [162]

Explanation:

Molar mass of Cu = 63.5g/mol

Moles of Cu

= 5.8g / (63.5g/mol) = 0.091mol (B)

8 0
2 years ago
A laser produces red light of wavelength 632.8 nm. Calculate the energy,
Ira Lisetskai [31]

Answer:

189.2 KJ

Explanation:

Data Given

wavelength of the light = 632.8 nm

Convert nm to m

1 nm = 1 x 10⁻⁹

632.8 nm = 632.8 x 1 x 10⁻⁹ = 6.328 x 10⁻⁷m

Energy of 1 mole of photon = ?

Solution

Formula used

                     E = hc/λ

where

E = energy of photon

h = Planck's Constant

Planck's Constant = 6.626 x 10⁻³⁴ Js

c = speed of light

speed of light = 3 × 10⁸ ms⁻¹

λ = wavelength of light

Put values in above equation

                   E = hc/λ

                   E = 6.626 x 10⁻³⁴ Js ( 3 × 10⁸ ms⁻¹ / 6.328 x 10⁻⁷m)

                   E = 6.626 x 10⁻³⁴ Js (4.741 x 10¹⁴s⁻¹)

                  E = 3.141 x 10⁻¹⁹J

3.141 x 10⁻¹⁹J is energy for one photon

Now we have to find energy of 1 mole of photon

As we know that

1 mole consists of  6.022 x10²³ numbers of photons

So,

     Energy for one mole photons = 3.141 x 10⁻¹⁹J x  6.022 x10²³

     Energy for one mole photons = 1.89 x 10⁵ J

Now convert J to KJ

1000 J = 1 KJ

1.89 x 10⁵ J = 1.89 x 10⁵ /1000 = 189.2 KJ

So,

energy of one mole of photons = 189.2 KJ

3 0
3 years ago
50 points plz help
EleoNora [17]

Answer: b

Explanation:

7 0
3 years ago
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