Double Replacement Reaction
KOH(s) ----> K⁺(aq)+OH⁻ (aq)
s-solid,
aq - aqueous
Answer:
<u>Optical purity = 76.9231 %</u>
<u>Specific rotation of mixture = - 97.6923 °</u>
Explanation:
The mass of the racemic mixture = 3 g
It means it contains R enantiomer = 1.5 g
S enantiomer = 1.5 g
Amount of Pure R = 10 g
Total R = 11.5 g
Total volume = 500 mL + 500 mL = 1000 mL = 1 L
[R] = 11.5 g/L
[S] = 1.5 g/L
Enantiomeric excess = = = 76.9231 %
<u>Optical purity = 76.9231 %</u>
Also,
Optical purity =
Optical rotation of pure enantiomer = −127 °
<u>Specific rotation of mixture = - 97.6923 °</u>
In an observation in an experiment, you want to write down as much detail as possible. So the answer would be false.