Thank you for posting your question here. I am just assuming to that the density of tin is <span>7.31 g/cm^3, you can change it it is not the number. Below is the solution. I hope it helps.
</span><span>95.04g x (1 cm³ / 7.31g) = 13.0 cm³</span>
Answer:
Specific gravity of mercury is 13.56 and it is an unit-less quantity.
Explanation:
Mass of the mercury = m = 607.0 lb = 275330.344 g
1 lb = 453.592 g
Volume of the mercury = v = 

Density of the mercury = d=
d = 13.56 g/mL
Specific gravity of substance = Density of substance ÷ Density of water

Specific gravity of mercury :
(unit-less quantity)
It can be done. Normally the boiling point of water is 100°C. It will boil at temperature greater than 100°C more quickly. Water can be boiled at 95°C but for that the atmospheric pressure of the water should be decreased which will decrease the boiling point of water.
<h3>
Concept :</h3>
To boil water at 95°C, decrease the atmospheric pressure.
At 105°C, the water will be boiling quickly than normal at 100°C.
Answer:
Explanation:"Watch the video and identify which of the following statements are correct." Excuse no video
It can allow the molecule (like water) to be polar because it has a negative and positive side to it (oxygen holds the negatives tight causing the hydrogens to be positive).