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Rashid [163]
4 years ago
13

Classify these substances. More than one answer may apply in each case.

Chemistry
1 answer:
enyata [817]4 years ago
3 0

Answer: H_2 :  Pure substance, Element

O_2 : Pure substance , Element

H_2O:  Pure substance, Compound

Explanation:

Element is a pure substance which is composed of atoms of similar elements.It can not be decomposed into simpler constituents using chemical reactions.Example: H-2 and O_2

Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.It can be decomposed into simpler constituents using chemical reactions. Example: H_2O

Heterogeneous Mixture : Mixture that has its different components mixed unevenly within the substance . Example: Air

Homogeneous Mixture : Mixture that has its different components mixed evenly within the substance. Example: sugar dissolved in water

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Calculate the mass of copper that could be made from 4.0g of copper oxide
Licemer1 [7]

The mass of copper that will be produced from copper oxide is determined as 3.19 g.

<h3>Mass of copper produced from copper oxide</h3>

The mass of copper that will be produced from copper oxide is calculated as follows;

2Cu + O₂  -----> 2CuO

2          1             2

2(63.5) ------------ 2(79.5)

x ---------------------- 4 g

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x = 3.19 g

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3 years ago
How many grams of testosterone, C19H28O2 (288.4 g/mol), must be dissolved in 299.0 grams of benzene to reduce the freezing point
iVinArrow [24]

Answer: 8.42 grams of testosterone

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=0.500^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

K_f = freezing point constant  of benzene= 5.12^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (benzene)= 299.0 g = 0.299 kg

Molar mass of solute testosterone= 288.4 g/mol

Mass of solute testosterone added = ?

0.500=1\times 5.12\times \frac{xg}{288.4 g/mol\times 0.299kg}

x=8.42g

Thus 8.42 grams of testosterone must be dissolved in 299.0 grams of benzene to reduce the freezing point by 0.500°C.

8 0
4 years ago
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