First, draw the 2-hexene. Th is is a molecule of six carbons with a double bond in the second carbon:
CH3 - CH = CH2 - CH2 - CH2 - CH3
Secong, put one Br on the second carbon and one Br on the third carbon:
CH3 - CBr = CBr - CH2 - CH2 - CH3
Third, cis means that the two Br are placed in opposed positions, this is drawn with one Br up and the other down. So, you need to represent the position of the Br in the space:
H Br H H H
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H - C - C = C - C - C - C - H
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H Br H H H
The important fact to realize is that the two Br are in opposed sides of the molecule.
Answer:
uhhh im not a boy ima just answer this for points
Explanation:
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