Answer: Yes, two objects may have the same volume while having different masses. The object with a greater mass will be the one that contains more matter.
Explanation: Mass and volume are two different properties of matter. Mass is defined as the amount of matter that a body has. Volume is defined as the amount of space that a body occupies. Density is the property that relates mass with volume as
and is defined as the amount of matter that exists in a certain amount of space.
Because mass and volume are independent from each other, we can say that two objects can have different masses and have the same volume.
<u>For example</u>, imagine two identical containers that weigh the same and that are capable of containing a volume of 1 liter each. Then, one of the containers is filled with water, while the other one is filled with mercury. In this case the volume of the water and the volume of the mercury will be the same: 1 liter, however, if we weigh the containers again, we will find that the one that has mercury is heavier than the one that has water. This is due to the density of mercury being higher than the density of water. In other words, 1 liter of mercury provides more mass than the mass provided by 1 liter of water.
Then, according to the definition of mass, the object that contains more matter will be the one that has more mass, in the case of our example, that would be the liter of mercury.
Answer:
Explanation:
HF ,Hydrofluoric acid happens to be a weak acid and as we know that a weak acid is partially dissociated in water.
So when we dissolve HF in water it would subsequently dissociate into H⁺ and F⁻ions . The solution now would contain hydronium ion that is H+ ion.
The solution would also contain dissociated F⁻ ion and solvent H20 molecules.
The following reaction would take place:
HF+H₂O⇆H₃O⁺+F⁻
so the reaction in forward direction is the dissociation of HF into H₃O⁺(that is H⁺) and F⁻ion.
The backward reaction would be the recombination of H₃O⁺(that is H⁺) and F⁻ion to give back HF and H₂O
Answer:
Final pressure is 1.42atm
Explanation:
Based on Gay-Lussac's law, pressure of a gas is directely proportional to its absolute temperature. The equation of this law is:
P₁T₂ = P₂T₁
<em>Where P is pressure and T is absolute temperature of 1, initial state and 2, final state of the gas.</em>
In the problem, initial conditions are Standard Temperature and Pressure, STP, that are 1 atm and 273.15K.
If the final temperature is 115°C = 388.15K (115°C + 273.15 = 388.15K), using Gay-Lussac's law:
P₁T₂ = P₂T₁
1atmₓ388.15K = P₂ₓ273.15K
1.42atm = P₂
<h3>Final pressure is 1.42atm</h3>
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Answer:
Explanation:
Using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat (Joules)
m = mass (grams)
c = specific heat capacity (J/g°C)
∆T = change in temperature