Explanation:
The given data is as follows.
F = ![5.75 \times 10^{-16} N](https://tex.z-dn.net/?f=5.75%20%5Ctimes%2010%5E%7B-16%7D%20N)
q = ![1.6 \times 10^{-19} C](https://tex.z-dn.net/?f=1.6%20%5Ctimes%2010%5E%7B-19%7D%20C)
v = 385 m/s
= 0.876
Now, we will calculate the magnitude of magnetic field as follows.
B = ![\frac{F}{qv sin (\theta)}](https://tex.z-dn.net/?f=%5Cfrac%7BF%7D%7Bqv%20sin%20%28%5Ctheta%29%7D)
= ![\frac{5.75 \times 10^{-16} N}{1.6 \times 10^{-19} C \times 385 m/s \times 0.876}](https://tex.z-dn.net/?f=%5Cfrac%7B5.75%20%5Ctimes%2010%5E%7B-16%7D%20N%7D%7B1.6%20%5Ctimes%2010%5E%7B-19%7D%20C%20%5Ctimes%20385%20m%2Fs%20%5Ctimes%200.876%7D)
=
T
= 10.65 T
Thus, we can conclude that magnitude of the magnetic field is 10.65 T.
Answer:
While the bus is moving, luggage tends to remain in inertia of motion state. When the bus stops, the luggage tends to resist the change and due to inertia of motion it moves forward and may fall off. That's why it is advised to tie any luggage kept on the roof of a bus with a rope.
Answer:
If a negatively charged balloon is brought near one end of the rod but not in direct contact, then <u>the negative charges on the balloon repel the same amount of negative charges on the end of the rod that is close to the balloon</u>, and the positive charges stay at the balloon-side of the rod. The total charge of the rod is still zero, but the distribution of the charges are now non-uniform.
Using the equation for period length, you get an answer of about 4.1 seconds.
Area is 2-dimensional which means it has a length and a width area is measured in square units such as square inches, square feet or square meters. To find the area of a rectangle multiply the length by the width.