A scientist measures the number of flies in a room over time. The results are

a certain hydraulic jack is used for lifting load. a force of 250N is applied on a small piston with a diameter of 80cm while th

anzhelika [568]

The maximum mass of a load that can be lifted by the jack and the distance covered are:

m = 160.2 Kg

h = 25 cm

Given that a certain hydraulic jack is used for lifting load. a force of 250N is applied on a small piston with a diameter of 80cm while the diameter of the larger piston is 2.0m.

The parameters given are

$F_{1}$ = 250

$A_{1}$ = Area of the small piston = π $r^{2}$

$A_{1}$ = 22/7 x $0.4^{2}$

$A_{1}$ = 0.5 $m^{2}$

$F_{2}$ = ?

$A_{2}$ = Area of the large piston = π $r^{2}$

$A_{2}$ = π x 1

$A_{2}$ = 3.14 $m^{2}$

To calculate the force on the large piston, we will use the below formula

$F_{1}$ / $A_{1}$ = $F_{2}$ / $A_{2}$

Substitute all the parameters into the equation

250/0.5 = $F_{2}$ /3.14

$F_{2}$ = 1570 N

To calculate the maximum mass of a load that can be lifted by the jack, let us apply Newton second law

F = mg

1570 = 9.8m

m = 1570/9.8

m = 160.2 Kg

.(take g=9.81ms^-2)

If the applied force moves through a distance of 25cm, the distance through which the load is lifted will be

$F_{1}$ / 0.25 $A_{1}$ = $F_{2}$ / $A_{2}$ h

250/0.125 = 1570/3.14h

make h the subject of the formula

6280h = 1570

h = 1570/6280

h = 0.25 m

Therefore, the distance through which the load is lifted is 25 cm

Learn more here: brainly.com/question/13596980

5 0

2 years ago

How to find the period of a wave

____ [38]

The method to choose depends on what information you have, and
on what you can measure. Here are a few possible methods:

-- Measure the period. Start your clock when one peak
of the wave passes you. Stop the clock when the next
peak passes you. The time between the two peaks is
the wave's period.

-- Divide the wave's wavelength by its speed. That quotient
is the wave's period.

-- Use an electronic frequency meter to measure the wave's
frequency. Then take its reciprocal (divide ' 1 ' by it). The
result is the wave's period.

5 0

4 years ago

A balloon holds 5.00 mol of a mono-atomic gas at a temperature of 5.00oC and at a pressure of 1.20 atm. The gas isothermally abs

Nadya [2.5K]

The answer is b try it out man theusgavqhhw

7 0

3 years ago

A 73-kg person in a moving car stops during a car collision in a distance of 0.80 m . The stopping force that the air bag exerts

fredd [130]

Answer:

v₀ = 13.24 m / s

Explanation:

Let's use Newton's second law to find the average acceleration during the crash

F = m a

. a = F / m

a = 8000/73

a = 109.59 m / s²

Now we can use the kinematic equations to find the initial velocity, since when the velocity stops it is zero (v = 0)

v² = v₀² - 2 a x

v₀² = 2 a x

v₀ = √ 2 a x

v₀ = √ (2 109.59 0.80)

v₀ = 13.24 m / s

3 0

4 years ago

Read 2 more answers

The periodic table is an arrangment of the chemical elements, ordered by atomic number, into families, and by doing so illustrat

olya-2409 [2.1K]

Answer:

Option B) reactive to nonreactive

Explanation:

A) Solid to gas

This might apply, because most of the gases are to the right portion of the periodic table

There are just a few elements that are gases at room temperature; a total of 11: six noble gases (group 18), two halogens (group 17), oxygen (group 16), nitrogen (group 15), and hydrogen (group 1).

Hydrogen is an exception to this trend because they are in the left part of the periodic table.

B) Reactive to nonreactive

The most reactive metals are in group 1 (alkali metals) and the most reactive nonmentals are in the group 18 (halogens). Hence, it is false that the from left to right the preperties go from reactive to nonreactive.

Hence, this is the one that cannot apply.

C) Metal to metalloid to nonmetal

It is true that the metallic character of the elements decreases from left to right; the metals are to the left, going to the right you find some metalloids, and further to the right you find the nonmetals.

Hence, this trend is correct.

D) Increasing number of outer-shell electrons

The number of outer-shell electrons definetly increase from left to right.

The number of electrons in neutral atoms equals the number of protons (to balance the positive and negative charges). Since, the atomic number (the number of protons) increase from left to right, the number of electrons also increase.

In a period (a row of the periodic table) the electrons add to the same outer-shell, then you will find that the number of electrons of the outer-shell increase from left to right. Hence, this is also a correct trend.

In conclusion, the only trend that does not apply is the described by the option B).

4 0

3 years ago

Read 2 more answers