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finlep [7]
3 years ago
13

Compute the resistance of a hardened copper rod 2 meters long and 8 mm in diameter if resistivity of the material is 1.756 x 10^

(-8) ohm-meters?
Physics
1 answer:
ryzh [129]3 years ago
4 0

Answer:

<em>The resistance of the copper rod =  4.39×10⁻¹⁵ Ohms.</em>

Explanation:

<em>Resistance: </em><em> This is the opposition to current flow in a circuit.</em>

<em>The S.I unit of resistance is Ohms.</em>

R = Aσ/L ........................... Equation 1

Where σ = resistivity of the copper, R = resistance of the copper rod,  A = cross sectional area of the copper, L = length of the copper rod.

<em>Given:</em>

σ = 1.756×10⁻⁸ ohm-meters, L = 2 meters.

But A = πd²/4

Where d = 8 mm = (8/1000) m = 0.0008 m, π = constant = 3.143

Therefore,

A = 3.143(0.0008)²/4

A = 0.0000005 m²

<em>Substituting these values into equation 1,</em>

<em>R = 5×10⁻⁷×1.756×10⁻⁸/2</em>

<em>R = (8.78 ×10⁻¹⁵)/2</em>

<em>R = 4.39×10⁻¹⁵ Ohms.</em>

<em>Thus the resistance of the copper rod =  4.39×10⁻¹⁵ Ohms.</em>

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