Answer:
A 75.1 N and a direction of 152° to the vertical.
B 85.0 N at 0° to the vertical.
Explanation:
A) The interaction partner of this normal force has what magnitude and direction?
The interaction partner of this normal force is the component of the weight of the crate perpendicular to the ramp. <u>It has a magnitude of 85cos28° = 75.1 N and a direction of 180° - 28° = 152° to the vertical(since it is directed downwards perpendicular to the ramp).</u>
B) The normal and frictional forces are perpendicular components of the contact force exerted on the crate by the ramp. What is the magnitude and direction of the contact force?
Since this force has to balance the weight of the crate, its magnitude is 85.0 N. Its direction has to be vertically opposite to that of the weight.
Since the weight is 180° to the vertical (since it is directed downwards), this force is 0° to the vertical.
<u>So, this force has a magnitude of 85.0 N and a direction of 0° to the vertical.</u>
Answer:
The magnitude of the heat transfer rate from the compressor is 87.05 kW
Explanation:
Initial pressure of refrigerant = 4 bar
Final pressure of refrigerant = 12 bar
From steam table,
Internal energy at 4 bar (U1) = 2554 kJ/kg
Internal energy at 12 bar (U2) = 2588 kJ/kg
Change in internal energy (∆U) = U2 - U1 = 2588 - 2554 = 34 kJ
Work input (W) = 120 kJ/kg
Quantity of heat transfer (Q) = ∆U + W = 34 + 120 = 154 kJ/kg
Volumetric flow rate of refrigerant = 8 m^3/min = 8/60 = 0.133 m^3/s
Density of refrigerant = 4.25 kg/m^3
Mass flow rate = density × volumetric flow rate = 4.25 kg/m^3 × 0.133 m^3/s = 0.56525 kg/s
Q = 154 kJ/kg × 0.56525 kg/s = 87.05 kJ/s = 87.05 kW
Answer:
For 6.0 eV
0.5 nm, 1.45*10^6 m/s, 6.17*10^10 m/s, 1.45*10^6 m/s
For 600 eV
1.26*10^-3 nm, 2.66*10^8 m/s, 3.37*10^8 m/s, 2.66*10^8 m/s
Explanation:
See attachment for calculation
B. the air suddenly becomes charged between two oppositely charged objects
For speed you can differentiate the equation, for acceleration you can again differentiate the equation .
at t=0 the particle is slowing down , when you get equation for velocity put t=0 then only -1 is left
