1 answer:
The miracle year for Albert Einstein was the year 1905 within which he published so many renowned papers.
<h3>When was Einstein miracle year?</h3>
The miracle year for Albert Einstein was the year 1905 within which he published so many renowned papers in a short time and became very popular.
His mindset in that year was one that challenged the orthodox explanations and sought to think outside the box.
Learn more about Albert Einstein:brainly.com/question/2964376
#SPJ1
You might be interested in
I choose the option D.
The velocity is constant, so it’s acceleration is 0 m/s^2.
X = 2 + 15 x 1 + 0 = 17 m
Answer:
Noble gas element
Explanation:
because Noble gas element can neither loose nor gain electrons
Answer:
C) Mass
Explanation:
The mass of an object divided by its volume equals the density.
Hope this helps!
Answer:
<u>Resolving</u><u> </u><u>horizontally</u><u>.</u> :
![\sum d_{x} = - (17.0 \cos 20.0) - (11.0 \cos 35.0) + (30.0 \cos 50.0) + 0 \\ { \underline{d _{x} = - 5.702 \: m}} \\ \\ \sum d _{y} = (17.0 \sin 20.0) + 12.0 - (11.0 \sin 35.0) - (30.0 \sin 50.0) \\ { \underline{d _{y} = - 11.476 \: m}}](https://tex.z-dn.net/?f=%20%5Csum%20d_%7Bx%7D%20%3D%20%20-%20%2817.0%20%5Ccos%2020.0%29%20-%20%2811.0%20%5Ccos%2035.0%29%20%2B%20%2830.0%20%5Ccos%2050.0%29%20%2B%200%20%5C%5C%20%20%7B%20%5Cunderline%7Bd%20_%7Bx%7D%20%3D%20%20-%20%205.702%20%5C%3A%20m%7D%7D%20%5C%5C%20%20%5C%5C%20%20%5Csum%20d%20_%7By%7D%20%3D%20%2817.0%20%5Csin%2020.0%29%20%2B%2012.0%20-%20%2811.0%20%20%5Csin%2035.0%29%20-%20%2830.0%20%5Csin%2050.0%29%20%5C%5C%20%7B%20%5Cunderline%7Bd%20_%7By%7D%20%20%3D%20%20-%2011.476%20%5C%3A%20m%7D%7D)
therefore, for resultant:
![d = \sqrt{ {d _{y} }^{2} + d _{x} {}^{2} }](https://tex.z-dn.net/?f=d%20%3D%20%20%5Csqrt%7B%20%7Bd%20_%7By%7D%20%7D%5E%7B2%7D%20%2B%20d%20_%7Bx%7D%20%20%7B%7D%5E%7B2%7D%20%20%7D%20)
substitute:
![d = \sqrt{ {( - 5.702)}^{2} + {( - 11.476)}^{2} } \\ \\ d = \sqrt{164.211} \\ \\ { \boxed{ \boxed{ \bf{d = 12.8 \: m}}}}](https://tex.z-dn.net/?f=d%20%3D%20%20%5Csqrt%7B%20%7B%28%20-%205.702%29%7D%5E%7B2%7D%20%2B%20%20%7B%28%20-%2011.476%29%7D%5E%7B2%7D%20%20%7D%20%20%5C%5C%20%20%5C%5C%20d%20%3D%20%20%5Csqrt%7B164.211%7D%20%20%5C%5C%20%20%5C%5C%20%7B%20%5Cboxed%7B%20%5Cboxed%7B%20%5Cbf%7Bd%20%3D%2012.8%20%5C%3A%20m%7D%7D%7D%7D)
Answer:
1.69515 seconds
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
![v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-33^2}{2\times -8.5}\\\Rightarrow s=64.06\ m](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20s%3D%5Cfrac%7Bv%5E2-u%5E2%7D%7B2a%7D%5C%5C%5CRightarrow%20s%3D%5Cfrac%7B0%5E2-33%5E2%7D%7B2%5Ctimes%20-8.5%7D%5C%5C%5CRightarrow%20s%3D64.06%5C%20m)
The distance between the traffic and the car after braking is 120-64.06 = 55.94 m
Time = Distance / Speed
![\text{Time}=\frac{55.94}{33}\\\Rightarrow \text{Time}=1.69515\ seconds](https://tex.z-dn.net/?f=%5Ctext%7BTime%7D%3D%5Cfrac%7B55.94%7D%7B33%7D%5C%5C%5CRightarrow%20%5Ctext%7BTime%7D%3D1.69515%5C%20seconds)
The reaction time cannot be more than 1.69515 seconds