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1 year ago

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1 answer:

8 0

The miracle year for Albert Einstein was the year 1905 within which he published so many renowned papers.

<h3>When was Einstein miracle year?</h3>

The miracle year for Albert Einstein was the year 1905 within which he published so many renowned papers in a short time and became very popular.

His mindset in that year was one that challenged the orthodox explanations and sought to think outside the box.

Learn more about Albert Einstein:brainly.com/question/2964376

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The magnitude of each force is 208 N the force on the right is applied at an angle 36° and the mass of the block is 17 kg the co

djyliett [7]

Answer:

11.06m/s²

Explanation:

According to Newtons second law of motion

$\sm F_x = ma_x\\F_m - F_f = ma_x\\mgsin \theta - \mu R mgcos \theta = ma_x\\$

Given

Mass m = 17kg

Fm = 208N

theta = 36 degrees

g = 9.8m/s²

a is the acceleration

Substitute

208 - 0.148(17)(9.8)cos 36 = 17a

208 - 24.6568cos36 = 17a

208 - 19.9478 = 17a

188.05 = 17a

a = 188.05/17

a = 11.06m/s²

Hence the the magnitude of the resulting acceleration is 11.06m/s²

6 0

2 years ago

Janet ran 30 meters in 4 seconds,what is her speed.

lubasha [3.4K]

Answer:

7.5 meters per second

Explanation:

30 / 4 = 7.5

7.5 * 1 = 7.5

7.5 * 2 = 15

7.5 * 3 = 22.5

7.5 * 4 = 30

8 0

3 years ago

Read 2 more answers

The heating and cooling of molecules will make ____________________ change their state of matter.

Lapatulllka [165]

Answer:

energy

Explanation:

The heating and cooling of molecule will make energy change their state of matter.

7 0

2 years ago

Hi, so i have to find T1, can some1 help?

iragen [17]

30.1 N

Explanation:

Given:

$W_1 = 16\:\text{N}$

$W_2 = 8\:\text{N}$

Let's write the components of the net forces at the intersections. Note that the system is equilibrium so all the net forces are zero.

Forces involving W1:

$x:\:\:\:-T_1 + T_3\cos \alpha = 0\:\: \\ \text{or}\:\:T_2 = T_3\cos \alpha\:\:\:\:\:(1)$

$y:\:\:\:T_3\sin \alpha - W_1 = 0\:\:\: \\ \text{or}\:\:\:T_3\sin \alpha = W_1\:\:\:\:\:\:(2)$

Forces involving W2:

$x:\:\:\:T_1\sin 53 - T_3\sin \alpha = W_2\:\:\:\:\:\:\:(3)$

$y:\:\:\:T_4 - T_1\cos 53 - T_3\cos \alpha = 0\:\:\:\;(4)$

Substitute (2) into (3) and we get

$T_1\sin 53 - W_1 = W_2$

Solving for $T_1$ ,

$T_1 = \dfrac{W_1 + W_2}{\sin 53} = 30.1\:\text{N}$

7 0

2 years ago

Is a bike standing still potential or kinetic?

BartSMP [9]

Answer:

potential

Explanation:

Potential energy is stored

Plz mark brainliest

6 0

2 years ago