Answer:
Explanation:
Physical development refers to the growth, physical and biological changes that happens in the humans body between birth and till they get to adolescence stage. There is development in brain, senses, they way they talk, physical appearance e.r.c.
Examples of these include, as humans grow, there is an increase in the way they interact with other people.
Babies tend to interact and learn new words even as their sense organs are been developed.
Cognitive development refers to how children develop in knowledge, skills, they way they think, their disposition and problem solving ability. These help children to think and understand their environment better.
Psychosocial development entails psychological and social development and it refers to how human personality is developed, acquiring social attitudes and skills from young age to adult. It entails how humans interact with their environment.
Moral development entails changes that occur in humans from childhood to adulthood by possesing the the skills and ability to know what is right and what is wrong i.e an understanding of morals behavior.
8 miles per hour
because if it is moving at 4 miles every half hour that means you have to multiply it by two to get it in miles per hour and we all know that 4 times 2 is 8 so it would be 8 miles per hour =)
Answer:
a) 17.49 seconds
b) 13.12 seconds
c) 2.99 m/s²
Explanation:
a) Acceleration = a = 1.35 m/s²
Final velocity = v = 85 km/h = 
Initial velocity = u = 0
Equation of motion
Time taken to accelerate to top speed is 17.49 seconds.
b) Acceleration = a = -1.8 m/s²
Initial velocity = u = 23.61\ m/s
Final velocity = v = 0
Time taken to stop the train from top speed is 13.12 seconds
c) Initial velocity = u = 23.61 m/s
Time taken = t = 7.9 s
Final velocity = v = 0
Emergency acceleration is 2.99 m/s² (magnitude)
Answer:
solution:
dT/dx =T2-T1/L
&
q_x = -k*(dT/dx)
<u>Case (1) </u>
dT/dx= (-20-50)/0.35==> -280 K/m
q_x =-50*(-280)*10^3==>14 kW
Case (2)
dT/dx= (-10+30)/0.35==> 80 K/m
q_x =-50*(80)*10^3==>-4 kW
Case (2)
dT/dx= (-10+30)/0.35==> 80 K/m
q_x =-50*(80)*10^3==>-4 kW
Case (3)
q_x =-50*(160)*10^3==>-8 kW
T2=T1+dT/dx*L=70+160*0.25==> 110° C
Case (4)
q_x =-50*(-80)*10^3==>4 kW
T1=T2-dT/dx*L=40+80*0.25==> 60° C
Case (5)
q_x =-50*(200)*10^3==>-10 kW
T1=T2-dT/dx*L=30-200*0.25==> -20° C
note:
all graph are attached
<span>The multiple reflection of a single sound wave is echo</span>
