Answer:
Carbon has 6 electrons.
Before I answer, here's what you need to know.
There are 7 shells. Each shell can hold a certain amount of electrons.
1: 2
2: 8
3: 18
4: 32
5: 32
6: 18
7: 8
Carbon has 6 electrons, remember? So shell 1 is already completely filled. Shell 1 completely full, so onto shell 2.
Shell 2 needs 8 electrons, but carbon only has 4 to give, so 2, 4.
I hope this helps!
Answer:
The answer is 50 Nm
Explanation:
<h3><u>Given</u>;</h3>
- Applied Force = 50 Newton
- Total Displacement = 1 meter
<h3>
<u>To </u><u>Find</u>;</h3>
Here,
W = F • d
W = 50 • 1
W = 50 Nm
Thus, Work done is 50 Nm
<u>-TheUnknownScientist 72</u>
I believe it is called or referred to as the "Jet Stream". During World War II, allied pilots encountered high speed winds in the upper air. They named those winds after the fastest planes they came up against: fighters equipped with jet engines! Jet stream winds in winter time can reach up to 300 MPH as well!
The question is oversimplified, and pretty sloppy.
Relative to the Earth . . .
The Moon is in an elliptical orbit around us, with a period of
27.32... days, and with the Earth at one focus of the ellipse.
Relative to the Sun . . .
The Moon is in an elliptical orbit around the Sun, with a period
of 365.24... days, and with the Sun at one focus of the ellipse,
and the Moon itself makes little dimples or squiggles in its orbit
on account of the gravitational influence of the nearby Earth.
I'm sorry if that seems complicated. You know that motion is
always relative to something, and the solar system is not simple.
In BPC
tan\theta =a/b = 3/4
\theta = tan^-1(0.75)
\theta = 36.87 deg
BP = sqrt(a^2 + b^2) = sqrt((3)^2 + (4)^2) = 5 m
Eb = k Q/BP^2 = (9 x 10^9) (16 x 10^-9)/5^2 = 5.76 N/C
Ea = k Q/AP^2 = (9 x 10^9) (16 x 10^-9)/4^2 = 9 N/C
Ec = k Q/CP^2 = (9 x 10^9) (16 x 10^-9)/3^2 = 16 N/C
Net electric field along X-direction is given as
Ex = Ea + Eb Cos36.87 = (9) + (5.76) Cos36.87 = 13.6 N/C
Net electric field along X-direction is given as
Ey = Ec + Eb Sin36.87 = (16) + (5.76) Sin36.87 = 19.5 N/C
Net electric field is given as
E = sqrt(Ex^2 + Ey^2) = sqrt((13.6)^2 + (19.5)^2) = 23.8 N/C
