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4 years ago

Which is the correct formula for finding the frequency of an electromagnetic wave? f = c – f = f = + c f =

Physics

1 answer:

liubo4ka [24]4 years ago

6 0

The answer for the online test is going to be the last one, D

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Momentum data about the same objects in the same closed system is shown below.

nalin [4]

Answer:

the value of x is 3.7 because they are arranged in a particular manner.

6 0

4 years ago

Read 2 more answers

You are on a train that is traveling at 3.0 m/s along a level straight track. Very near and parallel to the track is a wall that

loris [4]

Questions Diagram is attached below

Answer:

$T=2.08s$

Explanation:

From the question we are told that:

Speed of Train $V=3.0m.s$

Angle $\theta=12\textdegree$

Height of window $h_w=0.90m$

Width of window $w_w=2.0m$

The Horizontal distance between B and A from Trigonometric Laws is mathematically given by

$b=\frac{0.9}{tan12}$

$b=4.23$

Therefore

Distance from A-A

$d_a=2.0+4.23$

$d_a=6.23$

Therefore

Time Required to travel trough d is mathematically given as

$T=\frac{d_a}{v}$

$T=\frac{6.23}{3}$

$T=2.08s$

5 0

3 years ago

The following is current scientific evidence supporting the nebular theory on the formation of the solar system. the composition

andreyandreev [35.5K]

All planets orbit the sun in a plane, all the planets orbit the sun in the same direction, most of the planets rotate in the same direction. I'm not sure when and answer ends or begins on your question so you can choose from some of the answers I gave you.

6 0

3 years ago

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- What is the mass of a bowling ball that weights 80 Newtons on Earth?

ch4aika [34]

I’d say it’s 8 or 80
Hopefully this helps sorry

3 0

4 years ago

Read 2 more answers

a 230-newton box rests on a plank 5 meters long. One end is 1.2 meters higher than the other end. Find the components of the for

NISA [10]

Answer:

55.3 N, 223.3 N

Explanation:

First of all, we can find the angle of the inclined plane.

We have:

L = 5 m the length of the incline

h = 1.2 m is the height

We also have the relationship

$h = L sin \theta$

where $\theta$ is the angle of the incline. Solving for the angle,

$\theta= sin^{-1} (\frac{h}{L})=sin^{-1} (\frac{1.2 m}{5 m})=13.9^{\circ}$

Now we can find the components of the weight of the box, which is the force that the box exerts on the plank. Calling W = 230 N the weight of the box, we have:

- Component parallel to the incline:

$W_{par} = W sin \theta = (230 N)(sin 13.9^{\circ}) =55.3 N$

- Component perpendicular to the incline:

$W_{per} = W cos \theta = (230 N)(cos 13.9^{\circ}) =223.3 N$

4 0

3 years ago