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marishachu [46]
3 years ago
10

Hi please help me find the answer to this questions ​

Mathematics
1 answer:
maxonik [38]3 years ago
5 0

Answer:

what is the question

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Which of these questions are equivalent to 1/4
tensa zangetsu [6.8K]
B) 2/8 that’s the answer :p
7 0
3 years ago
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Alternate angles explain
Tanzania [10]

Here is the required diagram .

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(0,3){2}{\line(1,0){4}}\qbezier(0,0)(0,0)(4,3)\qbezier(1,0)(1.2,0.35)(0.8,0.6)\qbezier(3,3)(2.8,2.65)(3.2,2.4)\put(2.5,0.02){\vector(1,0){0}}\put(1.5,3.02){\vector(-1,0){0}}\end{picture}

Alternate angles are equal .

4 0
3 years ago
Which graph represents a linear function?
pshichka [43]

Answer:

y + 2x = 10 (third option)

Step-by-step explanation:

We can see that every time x increases by one, y increases by -2, meaning that the slope is -2.

We also know that the y-intercept is 10 because that is the value of y when x is equal to 0.

Now, we can create the equation using the slope-intercept form (y = mx + b, where m is the slope and b is the y-intercept).

y = -2x + 10

If you look at the third option, that equation is just a rearranged form of our equation (y + 2x = 10).

This means that the third option is correct.

7 0
3 years ago
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Three green jelly bean, five red jelly beans and two orange jelly bean are in a bag.
IrinaVladis [17]

Answer:

3/50

Step-by-step explanation:

3 g, 5 r, 2 o

3 + 5 + 2 = 10

Orange = 2 jelly beans

Probability of selecting an orange jelly bean: 2/10 or 1/5

If you put the jelly bean back in, there is still 10 jelly beans.

Green = 3 jelly beans

Probability of selecting a green jelly bean: 3/10

Multiply the probabilities:

1/5 x 3/10

= 3/50

7 0
3 years ago
Read 2 more answers
Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is
Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since,  its head is twice as likely to occur as its tail.

p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n  = 3

p=\dfrac{2}{3}

q=\dfrac{1}{3}

Now,

P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0
3 years ago
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