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3 years ago

15

Shawn earns $16000 per month. He spent 1/4 of his income on food; 3/10 of the remainder on house rent and 5/21 of the remainder

on the education of children. How much money is still left with him

1 answer:

joja [24]3 years ago

4 0

Answer: 5485

Step-by-step explanation: 16000:4= 4000

4000:10= 400

400x3= 1200

1200:21 = 57

57x5= 285

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Two angles of a quadrilateral measure 130 and 10. The other two angles are in a ratio 2.9. What are the measures of those two a

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Answer:

check: 50+160+130+20 = 360

50:160 = 5 : 16

Step-by-step explanation:et the smaller of the unknown angles be 5x and the larger of the two be 16x

so 130+20+5x+16x = 360

21x = 210

x = 10

so the two missing angles are 50° and 160°

check: 50+160+130+20 = 360

50:160 = 5 : 16

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Consider the function f (x) = x2.

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Answer: The graph is shifted 2 units to the right.

Step-by-step explanation:

Given a function f(x), we know that one transformation rule is:

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3 years ago

Read 2 more answers

Suppose you do an analysis of the starting salaries of 100 recent Lehman graduates. You find that the average starting salary is

madreJ [45]

Answer:

a) (59180,60820)

b) (59020,60980)

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $60,000

Standard Deviation, σ = $5,000

Sample size, n = 100

a) 90% critical values

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.10} = 1.64$

$60000 \pm 1.64(\frac{5000}{\sqrt{100}} ) = 60000 \pm 820 = (59180,60820)$

b) 95% critical values

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$60000 \pm 1.96(\frac{5000}{\sqrt{100}} ) = 60000 \pm 980= (59020,60980)$

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3 years ago

Are the functions f(x) = (x^2-1)/(x-1) and g(x)= x+1 equal for all x?

Vinvika [58]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\$

$\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}
\\\\\\
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-------------------------------\\\\
\textit{they're, kinda, except that, when x = 1}
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g(x)=(1)+1\implies g(x)=2
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4 years ago

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Answer:

BIL is the answer to that one day

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