All categories

3 years ago

How do units of work and power compare

Physics

1 answer:

timurjin [86]3 years ago

3 0

Answer:

Jule

Explanation:

They each have the same units which is jule

You might be interested in

Do this work if someone give correct answer I make her brainliest do this worksheet please

alexira [117]

Answer:

a. Any one way then I can say that Aluminum sulfide has mass per mole of ≈150.2g while aluminum has mass per mole of 26.9g

b. Sulfur is an element but aluminum sulfide is a compound

c.Beryllium and chlorine

d. BeCl2

e.i. Metals form ions by losing electrons but nonmetals form ions by gaining electrons

ii.A metal can react with an acid to produce a salt a nonmetal doesnt

iii. A metal forms ionic compounds whilst nonmetals form covalent compounds

5 0

3 years ago

Find the value of 02?

TiliK225 [7]

My educated guess : 21.2 deg

3 0

3 years ago

HOLA NECESITO SABER SI LO QUE HICE ESTÁ BIEN ,POR FAVOR ,NO RESPONDAN POR RESPONDER SIMPLEMENTE, RESPONDAN SOLO SI SABEN ,ES PAR

liq [111]

Answer:

El índice es la tabla de contenidos de un documento. El desarrollo es el cuerpo de información contenida en un documento

Explanation:

4 0

3 years ago

A child has fallen while riding a bike. When should a bystander call 911 ?

kari74 [83]

Answer:

C Or D

Explanation:

The Child Should Get Checked On Before You Call The Police Thought,

4 0

3 years ago

Read 2 more answers

A horizontal beam of electrons initially moving at 4.0×10^7 m/s is deflected vertically by the vertical electric field between o

givi [52]

Answer:

$1.77\times 10^{-7}\ C/m^2$

0.000439077936334 m

Explanation:

q = Charge of electron = $1.6\times 10^{-19}\ C$

E = Electric field = $2\times 10^{4}\ N/C$

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

d = Distance between plates = 2 cm (assumed)

m = Mass of electron = $9.11\times 10^{-31}\ kg$

The beam consists of electrons which means it has negative charge this means the upper plates will be positive and the lower plate will be negative.

The direction is upper to lower lower plate.

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

Electric flux is given by

$\phi=\epsilon_0E\\\Rightarrow \phi=8.85\times 10^{-12}\times 2\times 10^{4}\\\Rightarrow \phi=1.77\times 10^{-7}\ C/m^2$

The charge per unit area on the plates is $1.77\times 10^{-7}\ C/m^2$

Deflection is given by

$s=\dfrac{1}{2}\dfrac{qE}{m}(\dfrac{d}{v})^2\\\Rightarrow s=\dfrac{1}{2}\dfrac{1.6\times 10^{-19}\times 2\times 10^4}{9.11\times 10^{-31}}(\dfrac{0.02}{4\times 10^7})^2\\\Rightarrow s=0.000439077936334\ m$

The deflection is 0.000439077936334 m

7 0

3 years ago