the answer is heat engine
Answer:
The coefficient of static friction is 0.29
Explanation:
Given that,
Radius of the merry-go-round, r = 4.4 m
The operator turns on the ride and brings it up to its proper turning rate of one complete rotation every 7.7 s.
We need to find the least coefficient of static friction between the cat and the merry-go-round that will allow the cat to stay in place, without sliding. For this the centripetal force is balanced by the frictional force.

v is the speed of cat, 

So, the least coefficient of static friction between the cat and the merry-go-round is 0.29.
A. logic, would be your answer i believe!
Hope it helped you.
A. Acceleration is a wrong answer. Acceleration is the rate of change to in velocity. It involves a change in speed and direction.
B. Force is a wrong answer. Force is a directions from push/or pull.
C. Inertia is a correct. Inertia is a tendency of an object to stay at the rest or preserve its state of motion.
D. Velocity is a incorrect answer. Velocity is the placement of an object during a specific unit of time. It has two measurements are needed to determine velocity.
-Charlie
-Thank you so much!
Have a great day!
Answer:
Option A
D = m/v
Explanation:
Density is defined as mass per unit volume of an object. Therefore, D=m/v where m is the mass of the object and v is the volume
Therefore, option A is the right option