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Murljashka [212]
3 years ago
11

Two ropes are attached to a 35 kg object. The first rope applies a force of 20 N and the second applies a force of 55 N. If the

two ropes are perpendicular to each other, what is the resultant acceleration of the object?
Physics
2 answers:
Vsevolod [243]3 years ago
4 0

Answer:

Explanation:

mass of the object, m = 35 kg

Force in one direction, F1 = 20 N

force in perpendicular direction, F2 = 55 N

The net force is given by

F=\sqrt{F_{1}^{2}+F_{2}^{2}}

F=\sqrt{20^{2}+55^{2}}

F = 58.5 N

Let a be the net acceleration.

By the newton's second law

F = m a

58.5 = 35 x a

a = 1.67 m/s²

Goshia [24]3 years ago
3 0

Answer:

a=1.672\ m.s^{-2}

Explanation:

Given:

  • mass of the object, m=35\ kg

forces by two mutually perpendicular ropes of the attached to the object:

  • F_x=20\ N
  • F_y=55\ N

<u>Now we find the resultant force effect due to the two given forces:</u>

F=\sqrt{F_x^2+F_y^2}

F=\sqrt{(20)^2+(55)^2}

F=58.52\ N

<u>Now the acceleration will be due to this resultant force:</u>

a=\frac{F}{m}

a=\frac{58.52}{35}

a=1.672\ m.s^{-2}

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