The substitution product that is supposed to be favoured. The product with retention of configuration is expected to predominate slightly because the leaving group blocks the nucleophile.
<h3>What is a substitution product?</h3>
A substitution product is a product that is gotten from a reaction in which a group of reactants is replaced by another group in the reaction.
Therefore, the substitution product is supposed to be favoured. The product with retention of configuration is expected to predominate slightly because the leaving group blocks the nucleophile.
Learn more about substitution reaction below.
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Answer: C) the splitting of a nucleus released a large burst of energy
Explanation:
nuclear fission occurs when an isotope (usually unstable) is hit with particles such as neutrons and splits, resulting in an extreme burst of energy.
for instance, the atomic bombs developed by the U.S. during WWII were products of nuclear fission in which plutonium-239 and uranium-235 were struck by a neutron that hit either nucleus of either isotope. The result was the neclus split into fragments that released huge amounts of energy snd the fission process became self-sustaining as neutrons produced by the splitting nucleus hit other nuclei and produce more fission, causing a chain reaction.
The mass of 63 ml sample : 79.38 g
<h3>Further explanation</h3>
Given
20 ml and 25.2 g of glycerol
Required
The mass of 63 ml sample
Solution
Density is the ratio of mass per unit volume
Density formula:
Density of glycerol :
= m : V
= 25.2 g : 20 ml
= 1.26 g/ml
Mass of 63 ml sample :
= density x volume
= 1.26 g/ml x 63 ml
= 79.38 g
Answer:
4054 kcal of heat is released during complete combustion of 354 g of octane.
Explanation:
Heat of combustion of 1 mol of octane is 
kcal
Molar mass of octane = 114.23 g/mol
We know, no. of moles = (mass)/(molar mass)
So, kcal of heat is released during complete combustion of 114.23 g of octane.
So, amount of heat is released during complete combustion of 354 g of octane = 
kcal = 4054 kcal
Hence 4054 kcal of heat is released during complete combustion of 354 g of octane.
Answer:
The net charge on each lysine molecule would be -1.
Explanation:
- <u>When the pH is above 2.2</u> the deprotonated form of the carboxylic acid is more present, while the amino group and side chain (which is also amino) remain protonated (with a positive charge):
R-COOH ↔ R-COO⁻
R-NH₃⁺
R'-NH₃⁺
Net charge = +1
- <u>When pH is above 9.0</u>, the carboxyl group remains deprotonated, while the amino group is deprotonated and the side chain is protonated:
R-COOH ↔ R-COO⁻
R-NH₂
R'-NH₃⁺
Net charge = 0
- <u>When pH is above 10.5</u>, the carboxyl group remains deprotonated, while both the amino group and the side chain are deprotonated:
R-COOH ↔ R-COO⁻
R-NH₂
R'-NH₂
Net charge = -1
So at pH=13 (which is above 10.5) the net charge is -1.
