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erik [133]
3 years ago
7

Plz help with this........​

Chemistry
1 answer:
Elodia [21]3 years ago
3 0
<h2>GREETINGS!</h2><h2>_____________________________________</h2><h3>Answer:</h3>

ITS C_{4}H_{10} AND C_{5}H_{12}

<h2>_____________________________________</h2><h3><u>GENERAL FORMULA OF ALKANE</u></h3><h3>                    C_{n}H_{2n+2}</h3>

Where n is the number of CARBONS

<h2>_____________________________________</h2>

A)

By using the General Formula of Alkanes having 4 carbon atoms is

                        C_{4}H_{2x4+2}

                        C_{4}H_{10}

C)

By using the General Formula of Alkanes having 5 carbon atoms is

                         C_{5}H_{2x5+2}

                         C_{5}H_{12}

<h2>_____________________________________</h2>

IF YOU USE THE SAME FORMULA FOR THE OTHER TWO OPTIONS THE OUTCOME WILL NOT BE AS SAME AS GIVEN IN THE QUESTION SO THOSE TWO ARE CAN NOT BE OUR ANSWER

<h2>_____________________________________</h2><h2>HOPE THIS HELPS!</h2>

                       

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1. Show that heat flows spontaneously from high temperature to low temperature in any isolated system (hint: use entropy change
Inga [223]

Answer:

1 ) Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

2) ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

Explanation:

<u>1) To show that heat flows spontaneously from high temperature to low temperature </u>

example :

Pick two(2) solid metal blocks with varying temperatures ( i.e. one solid block is hot and the other solid block is cold )

Place both blocks for time (t ) in an insulated system to reduce heat loss or gain to or from the environment

Check the temperature of both blocks after time ( t ) it will be observed that both blocks will have same temperature after time t ( first law of thermodynamics )

Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

<u>2) Entropy change for Decomposition of mercuric oxide </u>

2HgO (s) → 2Hg(l) + O₂ (g)

Δs = positive

there is transition from solid to liquid and the melting point of mercury ( the point at which reaction will take place ) = 500⁰C

hence ΔSdecomposition = S⁻ Hg  -  S⁻ HgO =

Δh of reaction = 181.6 KJ

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A metallurgical firm wishes to dispose of 1200 gallons of waste sulfuric acid whose molarity is 1.05 M. Before disposal, it will
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Answer:

The balanced chemical equation for this process:

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Explanation:

The balanced chemical equation for this process

H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)

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Cost of 778.03 pounds of slaked lime  = $0.25 × 778.03 = $194.51

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