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erik [133]
3 years ago
7

Plz help with this........​

Chemistry
1 answer:
Elodia [21]3 years ago
3 0
<h2>GREETINGS!</h2><h2>_____________________________________</h2><h3>Answer:</h3>

ITS C_{4}H_{10} AND C_{5}H_{12}

<h2>_____________________________________</h2><h3><u>GENERAL FORMULA OF ALKANE</u></h3><h3>                    C_{n}H_{2n+2}</h3>

Where n is the number of CARBONS

<h2>_____________________________________</h2>

A)

By using the General Formula of Alkanes having 4 carbon atoms is

                        C_{4}H_{2x4+2}

                        C_{4}H_{10}

C)

By using the General Formula of Alkanes having 5 carbon atoms is

                         C_{5}H_{2x5+2}

                         C_{5}H_{12}

<h2>_____________________________________</h2>

IF YOU USE THE SAME FORMULA FOR THE OTHER TWO OPTIONS THE OUTCOME WILL NOT BE AS SAME AS GIVEN IN THE QUESTION SO THOSE TWO ARE CAN NOT BE OUR ANSWER

<h2>_____________________________________</h2><h2>HOPE THIS HELPS!</h2>

                       

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A student uses a solution of 1.2 molar sodium hydroxide (NaOH) to calculate the concentration of a solution of sulfuric acid (H2
Mila [183]

From the calculations, the concentration of the acid is 0.24 M.

<h3>What is neutralization?</h3>

The term neutralization has to do with a reaction in which an acid and a base react to form salt and water only.

We have to use the formula;

CAVA/CBVB = NA/NB

CAVANB =CBVBNA

The equation of the reaction is; 2NaOH + H2SO4 ----> Na2SO4 + 2H2O

CA = ?

CB = 1.2 M

VA =  50 mL

VB = 20 mL

NA = 1

NB = 2

CA = CBVBNA/VANB

CA = 1.2 M * 20 mL * 1/ 50 mL * 2

CA = 0.24 M

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5 0
2 years ago
What is the minimum volume of 5.50 M HCl necessary to neutralize completely the hydroxide in 718.0 mL of 0.183 M NaOH
Deffense [45]

The volume of HCl required is 23.89 mL

Calculation of volume:

The reaction:

HCl + NaOH \rightarrow NaCl + H_2O

As HCl and NaOH react in 1 : 1 ratio.

Volume of NaOH= 718 mL

Concentration= 0.183M

Volume of HCl= ?

Concentration= 5.50M

Using the dilution formula:

M_1\times V_1(NaOH)= M_2\times V_2(HCl)

0.183\times 718= 5.50 \times V_2\\V_2=\frac{131.394}{5.50} \\V_2 = 23.89 \,mL

Therefore,

Volume of HCl required will be 23.89 mL.

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6 0
2 years ago
Can someone please help
Ratling [72]

Answer:

1. c) shiny

2) True. Reactivity is a chemical property.

6 0
3 years ago
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How many protons does silicon have? <br> a. 2 <br> b. 14 <br> c. 28 <br> d. 28.08
EleoNora [17]
The answers is, B. 14
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3 years ago
Someone please help me!!!!
Artyom0805 [142]

Double replacement :

2Na₃PO₄+3CaCl₂⇒6NaCl + Ca₃(PO₄)₂

<h3>Further explanation</h3>

1. A single replacement reaction is a chemical reaction in which one element replaces the other elements of a compound to produce new elements and compounds

2. Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product

3. Combination/syntesis : 2 or more reactants combine to form a new compound

4. Decomposition : the reactant is decomposed into 2/more products

If we look at the reaction options available, all of them can be included in the double replacement reaction, but we only choose the reaction from Sodium phosphate and Calcium chloride which leads to options: C because it is balanced (from the number of atoms in the same reactant and product) and is in accordance with the chemical formula of each compound (both products and reactants)

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