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lorasvet [3.4K]
3 years ago
14

Human fingers are very sensitive, detecting vibrations with amplitudes as low as 2.0x10^-5m. Consider a sound wave with a wavele

ngth exactly 1000 times greater than the lowest amplitude detectable by fingers. What is this waves frequency​
Physics
1 answer:
Kobotan [32]3 years ago
3 0

Answer:

18,850 Hz

Explanation:

We need to figure out the wavelength of the sound wave.

Thus,

Wavelength = 1000 * Lowest Amplitude Wave

Wavelength = 1000 * 2.0 * 10^(-5)

Wavelength = 0.02

Or,

\lambda=0.02

Now, we need the frequency of this wave. It goes by the formula:

f=\frac{v}{\lambda}

Where

f is the frequency in Hz

v is the speed of sound in air (to be 377 m/s)

\lambda is the wavelength (we found to be 0.02)

Substituting, we find the frequency:

f=\frac{v}{\lambda}\\f=\frac{377}{0.02}\\f=18850

The wave has frequency of 18,850 Hz

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Compute the dot product of the vectors u and v​, and find the angle between the vectors. Bold v equals 7 Bold i minus Bold j and
OLga [1]

Answer:

\theta = 106.3 degree

Explanation:

As we know that

\vec w = -\hat i + 7\hat j

\vec v = 7\hat i - \hat j

also we know that

\vec v. \vec w = -14

it is given as

\vec v. \vec w = (-\hat i + 7\hat j).(7\hat i - \hat j)

\vec v. \vec w = - 7 - 7 = -14

also we can find the magnitude of two vectors as

|v| = \sqrt{(-1)^2 + (7)^2}

|v| = \sqrt{50}

similarly we have

|w| = \sqrt{(7^2) + (-1)^2}

|w| = \sqrt{50}

now we know the formula of dot product as

\vec v. \vec w = |v||w| cos\theta

-14 = (\sqrt{50})^2cos\theta

\theta = cos^{-1}(\frac{-14}{50})

\theta = 106.3 degree

3 0
3 years ago
During a summer with little rainfall, your house on a hill slope experiences an interval during which your well runs dry. You ha
irina1246 [14]

Answer and Explanation:

You don't have water because of two possible reasons:

  1. Because of the summer and the little rain, the underwater supply goes low.
  2. The slope in the hill you live makes the underground water goes down by the effect of gravity. Imagine the underground water like a small tank, when the water is reduced for any reason the bottom of the tank will have the remaining water, while the top part will be "empty".

6 0
3 years ago
Which could result from untreated diabetes check all that apply A .Asthma B. Numbness in hands and feet C.Exhaustion D.Weight lo
grigory [225]

With the exception of Asthma, all of those things, and a lot more that you don't want, could result from untreated diabetes.

3 0
3 years ago
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How much heat is needed to raise the temperature of an empty 2.0 x 101 kg vat made of
scZoUnD [109]

Answer:

Q = 7272 Kilojoules.

Explanation:

<u>Given the following data;</u>

Mass = 2.0*101kg = 202kg

Initial temperature, T1 = 10°C

Final temperature, T2 = 90°C

We know that the specific heat capacity of iron = 450J/kg°C

*To find the quantity of heat*

Heat capacity is given by the formula;

Q = mcdt

Where;

  • Q represents the heat capacity or quantity of heat.
  • m represents the mass of an object.
  • c represents the specific heat capacity of water.
  • dt represents the change in temperature.

dt = T2 - T1

dt = 90 - 10

dt = 80°C

Substituting the values into the equation, we have;

Q = 202*450*80

Q = 7272KJ or 7272000 Joules.

6 0
3 years ago
The gravitational force, F, between an object and the Earth is inversely proportional to the square of the distance from the obj
andreev551 [17]
<h2>Weight of astronaut 2450 miles above the Earth is 80.38 pounds</h2>

Explanation:

Given that gravitational force, F, between an object and the Earth is inversely proportional to the square of the distance from the object and the center of the Earth.

             F=\frac{k}{r^2}

Where F is gravitational force  between an object and the Earth, r is the distance from the object and the center of the Earth and k is a constant.

Radius of Earth = 4000 miles

In case 1 an astronaut weighs 209 pounds on the surface of the Earth,

              209=\frac{k}{4000^2}\\\\k=3.344\times 10^9

Now we need to find weight of astronaut 2450 miles above the Earth    

              r = 4000 + 2450 = 6450 miles

               F=\frac{k}{6450^2}\\\\F=\frac{3.344\times 10^9}{6450^2}=80.38pounds

Weight of astronaut 2450 miles above the Earth is 80.38 pounds  

3 0
3 years ago
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