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galina1969 [7]
3 years ago
14

The time it takes for a dragster to cross the finish line is unknown. The dragster accelerates from rest at 26 m/s2 for a quarte

r-mile (402 m). What is the final velocity of the dragster?
Physics
1 answer:
exis [7]3 years ago
7 0

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{v}^{2} -  {v(0)}^{2} = 2.a.∆x

v = final \:  \: velocity

v(0) = the \:  \: velocity \:  \: in \:  \: the \:  \: rest \:  \: which \: \: is \:  \: zero \\

a = acceleration

∆x = covered \:  \: distance

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

{v}^{2} -  ({0})^{2} = 2 \times 26 \times 402

v =  \sqrt{2 \times 26 \times 402}

v =  \sqrt{20904}

v = 144.58 \:  \:  \frac{m}{s}

Done...

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Answer:

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Average velocity: distance / time

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Going faster and slowing dowm

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4 0
2 years ago
In the final situation below, the 8.0 kg box has been launched with a speed of 10.0 m/s across a frictionless surface. Find the
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Explanation:

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Final Kinetic energy of the box = initial elastic potential energy of the spring

K.E = Ux

¹/₂mv² = Ux

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8 0
3 years ago
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4000 + 50T = 4000 - 50T

0 = 100 T

T = 0° C

Thus, the final temperature is 0° C

3 0
2 years ago
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