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Temka [501]
2 years ago
10

A 30 kg dog runs at a speed of 15 What is the dog's kinetic energy?

Physics
1 answer:
sattari [20]2 years ago
3 0
Ke= 1/2 mv ^ 2
15x 15 = 225
225 x 30 = 6750
6750/2 = 3375 J
Ke = 3375 J
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MaRussiya [10]

Answer:

A - Sublimation

B - Evaporation

C - Melting

Explanation:

The state of change present in A is Sublimation. Dry Ice is the most common example of Sublimation of everyday life

The state of change present in B is evaporation. Boiling water into water vapor is something that anyone can see.

The state of change present in C is called Melting. Think of Ice melting into a pool of water as the ice heats up.

5 0
3 years ago
Which of the following statements does NOT describe force?
Mila [183]

Answer: D

Explanation: Force can do everything else.

8 0
3 years ago
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A car moved with a constant speed of 104km/hr how long will it take to travel a distance of 422.9km?
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3 years ago
Which statement(s) accurately describe the conditions immediately before and after the firecracker explodes:
lidiya [134]

Answer:

Option C, The total momentum of the fragments is equal to the original momentum of the firecracker.

Explanation:

Kinetic energy of cracker cannot remain constant before and after explosion. It is so because in the process of burning and bursting some amount of kinetic energy is lost in the form of light and heat energy. While the total mass before and after the explosion remains constant due to which the momentum is conserved before and after the explosion

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8 0
3 years ago
A 78.5-kg man is standing on a frictionless ice surface when he throws a 2.40-kg book horizontally at a speed of 11.3 m/s. With
kirill [66]

Answer:

The man moves across the ice with a speed of 0.345m/s.

Explanation:

From the conservation of linear momentum, we have that the total linear momentum before the book throw is equal to the total linear momentum just after it. Since the initial velocity of the system is zero (so the initial momentum is zero), we have that:

m_mv_m+m_bv_b=0\\\\v_m=-\frac{m_b}{m_m} v_b

Where m_m is the mass of the man, m_b is the mass of the book, and v_m and v_b are their velocities. Plugging in the given values, we can compute the speed of the man (ignoring the negative sign, because we care about the magnitude, not the direction):

v_m=\frac{2.40kg}{78.5kg}(11.3m/s)=0.345m/s

In words, the resulting speed of the man is 0.345m/s.

8 0
3 years ago
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