a) 6.52 m/s^2
b) 23.47 km/hr^2
a) v = v0 + at --> 9 = 0 + a(1.38) --> a = 6.52
b) 6.52 m/s2 * 60 s2 / 1 min2 * 60 min2 / 1 hr2 = 23.47 km/hr2
Answer:
Explanation:
A. Using
E= ma/q
E=m/q(2s/t²)
So
E= 9.1x10^-31/1.6*10^-19( 2*4.5/ 3*10-12)
E=5.7NC
The electric field has to be downward since the force is positive that is upward
B.
The electron acceleration is of the order of 10^11 times greater so for practical purposes we neglect the effect of gravity
Answer:
<h2>10 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 2 × 5
We have the final answer as
<h3>10 N</h3>
Hope this helps you
Answer:
The distance from the top of the stick would be 2l/3
Explanation:
Let the impulse 'FΔt' acts as a distance 'x' from the hinge 'H'. Assume no impulsive reaction is generated at 'H'. Let the angular velocity of the rod about 'H' just after the applied impulse be 'W'. Also consider that the center of percussion is the point on a bean attached to a pivot where a perpendicular impact will produce no reactive shock at the pivot.
Applying impulse momentum theorem for linear momentum.
FΔt = m(Wl/2), since velocity of center of mass of rod = Wl/2
Similarly applying impulse momentum theorem per angular momentum about H
FΔt * x = I * W
Where FΔt * x represents the impulsive torque and I is the moment of inertia
F Δt.x = (ml² . W)/3
Substituting FΔt
M(Wl/2) * x = (ml². W)/3
1/x = 3/2l
x = 2l/3
