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Anna [14]
3 years ago
15

For the data set below, which of the following are true? {88, 79, 86, 93, 76, 80, 82, 72, 95, 79}

Mathematics
1 answer:
FrozenT [24]3 years ago
6 0
D. The interquartile range is 9
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Find the third order maclaurin polynomial. Use it to estimate the value of sqrt1.3
vodka [1.7K]

\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3} is the maclaurin polynomial and estimate value of \sqrt{1.3} is 1.14. This can be obtained by using the formula to find the maclaurin polynomial.

<h3>Find the third order maclaurin polynomial:</h3>

Given the polynomial,

f(x)=\sqrt{1+3x}=(1+3x)^{\frac{1}{2} }

The formula to find the maclaurin polynomial,

f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}

Next we have to find f'(x), f''(x) and f'''(x),

  • f'(x) = \frac{3}{2}(1+3x)^{-\frac{1}{2} }
  • f''(x) =-\frac{9}{4}(1+3x)^{-\frac{3}{2} }
  • f'''(x) = \frac{81}{8}(1+3x)^{-\frac{5}{2} }

By putting x = 0 , we get,

  • f(0)=(1+3(0))^{\frac{1}{2} }=1
  • f'(0) = \frac{3}{2}(1+3(0))^{-\frac{1}{2} }=\frac{3}{2}
  • f''(0) =-\frac{9}{4}(1+3(0))^{-\frac{3}{2} }=-\frac{9}{4}
  • f'''(0) = \frac{81}{8}(1+3(0))^{-\frac{5}{2} }=\frac{81}{8}

Therefore the maclaurin polynomial by using the formula will be,

\sqrt{1+3x}=f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}

\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}

To find the value of \sqrt{1.3}  we can use the maclaurin polynomial,

\sqrt{1.3} is  \sqrt{1+3x} with x = 1/10,

\sqrt{1+3(1/10)}=1+\frac{3}{2} (1/10)-\frac{9}{8} (1/10)^{2} + \frac{81}{8}(1/10)^{3}

\sqrt{1+3(1/10)}=\frac{18247}{16000} = 1.14

Hence \sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3} is the maclaurin polynomial and estimate value of \sqrt{1.3} is 1.14.

Learn more about maclaurin polynomial here:

brainly.com/question/24188694

#SPJ1

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A single bacterium is placed in a test tube and splits in two after one minute. After two minutes, the resulting two bacteria sp
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I THINK THAT ITS 1.414 AS THE ANSWER.
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if a 100 n weight sits on a scale in a express elevator, what will happen to the weight shown on the scale when the elevator acc
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The phrasing of the question is weird, but the mass should not change. The scale may read higher for a moment, but once the mass is brought up to the same velocity of the elevator, it should settle back to 100.

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Simplify the following √5 x 2√2
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try mopo quanda or guthmath

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Write 2 decimals whose product is 0.16
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0.4 and 0.4 or 0.8 and 0.2 

Hope this helps :)
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