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NikAS [45]
4 years ago
13

Iron and carbon monoxide are made by heating 5.53 kg of iron ore, Fe₂O₃, and carbon. What is the theoretical yield of iron in ki

lograms?
Chemistry
1 answer:
vfiekz [6]4 years ago
3 0

Answer:

Mass of Fe produced = 3.86785211069  ≈ 3.87 kg

Explanation:

From the question the chemical reaction can be written as follow :

Fe2O3 + C → Fe + CO  

Balance the equation

Fe2O3 + 3C → 2Fe + 3CO  

compute the molecular mass of Fe2O3 and atomic mass of Iron(Fe)

Molecular mass of Fe2O3 = 55.845(2) + 15.999(3) = 111.69 + 47.997 = 159.687 g

Atomic mass of iron = 55.845 g

From the balanced equation

159.687 g of Fe2O3  produces 2 ×  55.845 = 111.69 g of Fe(iron)

Convert the 5.53 kg to gram

1 kg = 1000 g

5.53 kg  = 5.53 × 1000 = 5530 g

since,

159.687 g of Fe2O3  produces 2 ×  55.845 = 111.69 g of Iron(Fe)

5530 g of  Fe2O3  will produce  

cross multiply

Mass of Fe produced =5530 × 111.69/159.687

Mass of Fe produced = 617645.7

/159.687

Mass of Fe produced = 3867.85211069  g

convert to kg

1000 g = 1 kg

3867.85211069   = 3867.85211069/1000

Mass of Fe produced = 3.86785211069  ≈ 3.87 kg

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Calculate ΔS° for the reaction: 4Cr(s) + 3O2(g) → 2Cr2O3(s), Substance: Cr(s) O2(g) Cr2O3(s), S°(J/K⋅mol): 23.77 205.138 81.2
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<u>Answer:</u> The value of \Delta S^o for the reaction is 1051.93 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]

For the given chemical reaction:

4Cr(s)+3O_2(g)\rightarrow 2Cr_2O_3(s)

The equation for the entropy change of the above reaction is:

\Delta S^o_{rxn}=[(2\times \Delta S^o_{(Cr_2O_3(s))})]-[(4\times \Delta S^o_{(Cr(s))})+(3\times \Delta S^o_{(O_2(g))})]

We are given:

\Delta S^o_{(Cr_2O_3(s))}=881.2J/K.mol\\\Delta S^o_{(O_2(g))}=205.13J/K.mol\\\Delta S^o_{(Cr(s))}=23.77J/K.mol

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(2\times (881.2))]-[(4\times (23.77))+(3\times (205.13))]\\\\\Delta S^o_{rxn}=1051.93J/K

Hence, the value of \Delta S^o for the reaction is 1051.93 J/K

5 0
4 years ago
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