Answer:
Part A: 2N₂O(g) ⇄ 2N₂(g) + O₂(g)
Part B: -r = K*[N₂O]²
Part C: K= k1*k2
Explanation:
Part A
To do the balance chemical question for the overall chemical reaction, we must sum the reaction of the steps, eliminating the intermediaries, which are the compounds that have the same amount both at reactants and products (bolded).
N₂O(g) ⇄ N₂(g) + O(g)
N₂O(g) + O(g) ⇄ N₂(g) + O₂(g)
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2N₂O(g) + O(g) ⇄ 2N₂(g) + O(g) + O₂(g)
2N₂O(g) ⇄ 2N₂(g) + O₂(g)
Part B
The velocity of the reaction (r) can be calculated based on the reactants or based on the products. Let's do it based on the disappearing of the reactant. Because it is disappearing, the variation at its concentration must be negative, so the rate will be negative.
Let's suppose its an elementary reaction, so, the concentration of the reactant must be elevated by its coefficient. And let's call the overall rate constant as K:
-r = K*[N₂O]²
Part C
Because the steps were summed, and the reactions were not multiplied by a constant or inverted, the constant K is just the multiplication of the constants of the steps:
K= k1*k2
This is a combustion reaction. Any reaction in which a hydrocarbon decomposes into carbon dioxide and water is classified as combustion. The energy used for the decomposition usually comes from intense heat, which is why combustion of a hydrocarbon almost always is associated with a source of fire.
Hi There! :)
<span>Which elements in the periodic table are metalloids or have semimetallic properties?
</span><span>Boron, Silicon, Germanium, Arsenic, Antimony, and Polonium are all metalloids. Some people consider Astatine a metalloid</span>
Moles KClO₃ = 0.239
<h3>Further explanation</h3>
Given
Reaction
2KClO₃(s) ⇒2KCl(s) + 3O₂(g)
P water = 23.8 mmHg
P tot = 758 mmHg
V = 9.07 L
T = 25 + 273 = 298 K
Required
moles of KClO₃
Solution
P tot = P O₂ + P water
P O₂ = P tot - P water
P O₂ = 758 - 23.8
P O₂ = 734.2 mmHg = 0.966 atm
moles O₂ :
n = PV/RT
n = 0.966 x 9.07 / 0.082 x 298
n = 0.358
From equation, mol ratio KClO₃ : O₂ = 2 : 3, so mol KClO₃ :
= 2/3 x mol O₂
= 2/3 x 0.358
= 0.239
Answer: 1.2 M
Explanation:
Given that:
volume of NaCl = 392 mL
Convert volume in milliliters to liters
(since 1000 mL = 1L
392 mL = 392/10000 = 0.392 L)
Concentration of NaCl = ?
Amount of moles of NaCl = 0.47 moles
Recall that the concentration of a solution depends on the amount of solute dissolved in a particular volume of solvent.
I.e Concentration in mol/L =
Amount in moles / Volume in liters
= 0.47 moles / 0.392 L
= 1.199 mol/L (Round up to the nearest tenth as 1.2 M)
Note that molarity is the same as concentration in moles per litres.
Thus, the molarity of 392 mL of solution that contains 0.47 mol NaCl is 1.2 M
