Which two statements describe organ systems working together to remove

Leonard designed a parallel circuit to light two light bulbs. But his circuit doesn’t work. Which two items in the circuit must

klasskru [66]

Answer : When a parallel circuit is built the voltage across each of the components remains the same, also the total current passed is the equal to sum of the currents passing through each components in the circuits.

When 2 or more components are tried to be connected in parallel they maintain the same potential difference (in voltage) across their ends of the circuit.

The potential differences across the components are the observed to be same in magnitude, and they have identical polarities between them.

Then, this same voltage is applicable to all circuit components connected in parallel.

So, if each bulb is wired to the battery in a separate loop, the bulbs will be in parallel series.

3 0

3 years ago

Balance the Chemical Equations MgF2 + Li2CO3---> MgCO3 + LiF Please Help

kirill115 [55]

Answer:

MgF2 + Li2CO3 ---> MgCO3 + 2LiF

Explanation:

4 0

3 years ago

The reaction: 2 CO(l) + O2(g) ⇄2 CO2(g) with a H = −25.0 kJ/mol, is at equilibrium. Which of the following lists three ways thi

elena-s [515]

Answer:

Option B and D both have 3 ways to shift the reaction to the right

Explanation:

The reaction 2 CO(l) + O2(g) ⇄2 CO2(g) is exothermic because ΔH = -25 kJ < 0 This means heat will be released

Therefore, increasing the temperature will shift the equilibrium to the left, while decreasing the temperature will shift the equilibrium to the right.

A. remove CO2, lower pressure and remove CO

⇒ Lowering the pressure will shift the equilibrium to the side with most moles of gas : On the left side there are 3 moles, on the right side 2 moles. By lowering the pressure, the equilibrium will shift to the left.

B remove CO2, raise pressure and add CO

⇒ By raising the pressure, the equilibrium will shift to the side with the lesser amount of moles of gas. This is the right side.

⇒ Remove CO2: the equilibrium will shift to the side of CO2 ,so the reaction will shift toward products to replace the product removed. (The right side).

⇒ Add CO: the equilibrium will shift to the side of CO2, so the reaction will shift toward the products side to reduce the added CO. (The right side).

C raise temperature, lower pressure and remove O2

⇒ Increasing the temperature will shift the equilibrium to the left

D add O2, raise pressure and lower temperature

⇒ decreasing the temperature will shift the equilibrium to the right

⇒ By raising the pressure, the equilibrium will shift to the side with the lesser amount of moles of gas. This is the right side.

⇒ Add O2: the equilibrium will shift to the side of CO2, so the reaction will shift toward the products side to reduce the added O2. (The right side).

E remove CO2, increase volume and lower temperature

⇒ decreasing the temperature will shift the equilibrium to the right

⇒ Remove CO2: the equilibrium will shift to the side of CO2 ,so the reaction will shift toward products to replace the product removed. (The right side).

⇒ Increase volume : with a pressure decrease due to an increase in volume, the side with more moles is more favorable. The equilibrium will shift to the left side.

8 0

3 years ago

CAN YOU EXPLAIN? How do static charges interact and how are they released

taurus [48]

Static electricity is the result of an imbalance between negative and positive charges in an object. These charges can build up on the surface of an object until they find a way to be released or discharged. ... The rubbing of certain materials against one another can transfer negative charges, or electrons.

5 0

3 years ago

The nucleus of most atoms is composed of

gulaghasi [49]

Answer:

protons

Explanation:

5 0

3 years ago