All categories

3 years ago

What is the weight of a 45 kg box? N

Physics

2 answers:

Aleks04 [339]3 years ago

7 0

45 kg * 9.8 m/s^2 = <u>441 N.</u>

3241004551 [841]3 years ago

7 0

Answer:

The force of a mass's weight is defined as its mass * acceleration due to gravity.

On Earth, g is about 9.8 m/s^2. This will be the acceleration due to gravity.

Then, 45 kg * 9.8 m/s^2 = 441 N.

You might be interested in

How much time would it take for the sound of thunder to travel 1,500 meters if sound travels at a speed of 330 m/sec?

Fittoniya [83]

(1,500 meters) x (1 sec / 330 meters) = (4 and 18/33) seconds

(4.55 sec, rounded)

8 0

4 years ago

Read 2 more answers

A tire measures 20 inches in diameter. How many revolutions will the tire have completed when it has traveled 100 yards? Express

Soloha48 [4]

<h2>Number of revolutions required to travel 100 yards is 57.</h2>

Explanation:

Diameter of tire,D = 20 inches

Perimeter of tire = πD

Perimeter of tire = π x 20 = 62.8 inches

Distance traveled = 100 yards

1 yard = 36 inches

Distance traveled = 100 x 36 = 3600 inches

In one revolution it travels 62.8 inches.

$\texttt{No of revolutions = }\frac{3600}{62.8}\\\\\texttt{No of revolutions = }57.32\\\\\texttt{No of revolutions = }57$

Number of revolutions required to travel 100 yards is 57.

8 0

3 years ago

Two small space probes have been slowed to 10m/s as they approach the moon from the same direction. Probe 1 has a mass of 86kg a

bulgar [2K]

Answer:

Explanation:

4 0

3 years ago

If the angular frequency of the motion of a simple harmonic oscillator is doubled, by what factor does the maximum acceleration

Nataly_w [17]

Answer:

When we double the angular velocity the maximum acceleration $(a_{max})$ will changes by a factor of 4.

Explanation:

Given the angular frequency $(\omega)$ of the simple harmonic oscillator is doubled.

We need to find the change in the maximum acceleration of the oscillator.

$a_{max}=A\omega^2$

Now, according to the problem, the angular frequency $(\omega)$ got doubled.

Let us plug $\omega=2\times \omega$ . Then the maximum acceleration will be $a_{max'}$

$a_{max}=A\omega^2$

$a_{max'}=A(2\times \omega)^2\\a_{max'}=A\times 4\omega\\a_{max'}=4A\omega$

$a_{max'}=4a_{max}$

We can see, when we double the angular velocity the maximum acceleration will changes by a factor of 4.

6 0

3 years ago

What is the net force of an object with a mass of 90.0 and accelerating at 3.0 m/s

Ksivusya [100]

The net force is 270 N

Explanation:

We can solve this problem by using Newton's second law, which states that the net force on an object is equal to the product between its mass and its acceleration:

$F=ma$

where

F is the force

m is the mass

a is the acceleration

In this problem, we have

m = 90.0 kg

$a=3.0 m/s^2$

Substituting, we find the net force on the object:

$F=(90.0)(3.0)=270 N$

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

3 0

3 years ago