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dlinn [17]
3 years ago
14

What is the weight of a 45 kg box? N

Physics
2 answers:
Aleks04 [339]3 years ago
7 0

45 kg * 9.8 m/s^2 = <u>441 N.</u>

3241004551 [841]3 years ago
7 0

Answer:

The force of a mass's weight is defined as its mass * acceleration due to gravity.

On Earth, g is about 9.8 m/s^2. This will be the acceleration due to gravity.

Then, 45 kg * 9.8 m/s^2 = 441 N.

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Seeing a police officer ahead and not being sure of the speed limit, a driver slows from 65 mi/hr to 55 mi/hr in 4.0 seconds, tr
Flauer [41]

Answer:

-1.13 m/s^2

Explanation:

The acceleration of the car is given by:

a=\frac{v-u}{t}

where

v is the  final velocity

u is the initial velocity

t is the time

Here we have to convert the velocities from mi/hr to m/s. Keeping in mind that

1 mi = 1609 m

1 h = 3600 s

We get:

u = 65 mi/h \cdot \frac{1609}{3600}=29.1 m/s\\v = 55 mi/h \cdot \frac{1609}{3600}=24.6 m/s

While the time interval is

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a=\frac{24.6 - 29.1}{4.0}=-1.13 m/s^2

3 0
3 years ago
Two point charges are fixed on the y axis a negative point charge q1-26 μC at y1 = +0.21 m and a positive point charge q2 art y2
11111nata11111 [884]

Answer:

3.13\times 10^{-5} C

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y_2=0.39 m

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Using the formula

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F_1=\frac{9\times 10^9\times 26\times 10^{-6}\times 8.1\times 10^{-6}}{(0.21)^2}

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Force on charge q due to point charge q2

F_2=\frac{9\times 10^9\times q_2\times 8.1\times 10^{-6}}{(0.39)^2}

F_2=4.79\times 10^5 q_2

F=F_1-F_2

28=42.98-4.79\times 10^5q_2

4.79\times 10^5q_2=42.98-28=14.98

q_2=\frac{14.98}{4.79\times 10^5}=3.13\times 10^{-5} C

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3 years ago
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Answer:

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