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Ivahew [28]
2 years ago
14

How long is a football field?

Physics
2 answers:
Nana76 [90]2 years ago
7 0

Answer:

91.44 meters or 300 feet

ycow [4]2 years ago
6 0

Answer:

100 yards

Explanation:

If comparing from actual playing field between the goal posts. Add another 10 yards for end lines. Making it 120 yards in length.

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A heavy, 6 m long uniform plank has a mass of 30 kg. It is positioned so that 4 m is supported on the deck of a ship and 2 m sti
Harman [31]

Answer:

about 1 meter

Explanation:

   

8 0
3 years ago
Select all of the following that describes momentum, p [mark all correct answers]
Inga [223]

Answer:

c. Momentum is the product of mass and velocity

e. Momentum is a vector quantity

g. Momentum has unit of kgm/s

Explanation:

Linear momentum P

P = m .v

m =mass

v=Velocity

If mass take in kg and velocity is in m/s then momentum p will be in kg.m/s.

1. momentum is the product of velocity and mass.

2.Momentum is a vector quantity.

3.Momentum have kg.m/s unit.

So the following option are correct.

c. Momentum is the product of mass and velocity

e. Momentum is a vector quantity

g. Momentum has unit of kgm/s.

Note-

1.Joule is the unit of energy.

2.One-half the product of mass and the square of the object's speed is known as kinetic energy.

7 0
3 years ago
An object with a mass of 70 kilograms is supported at a height 8 meters above the ground. What's the potential energy of the obj
alexira [117]
Ep= mgh

70 x 9.8 x 8

Ep= 5,488J
5 0
3 years ago
Two people pull on the wagon each with a constant 20N force. Both people pull to the left. What is the Net Force on the wagon?
eduard

Answer:

I dont understand what you are trying to ask

Explanation:

5 0
2 years ago
A conductor of radius r, length and resistivity ρ has resistance r. what is the new resistance if it is stretched to 4 times its
max2010maxim [7]
The resistance of a conductor is given by
R= \frac{\rho L}{A}
where L is the length of the wire, \rho the resistivity of the material and A the cross-sectional area.

We can see that if all the other quantities do not change, if the new length of the conductor is 4 times the original length: L'=4 L, then the new resistance is also 4 times the original value:
R'= \frac{\rho L'}{A}= \frac{\rho 4 L}{A}=4  \frac{\rho L}{A}=4 R
7 0
3 years ago
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