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Ipatiy [6.2K]
3 years ago
12

How a cold front affects weather.

Chemistry
2 answers:
Zielflug [23.3K]3 years ago
6 0

Answer:

Explanation:A cold front forms when a cold air mass pushes into a warmer air mass. Cold fronts can produce dramatic changes in the weather.  As the cold front passes, winds become gusty. There is a sudden drop in temperature, and also heavy rain, sometimes with hail, thunder, and lightning.

miskamm [114]3 years ago
4 0

Answer:

A cold front forms when a cold air mass pushes into a warmer air mass. Cold fronts can produce dramatic changes in the weather. ... As the cold front passes, winds become gusty. There is a sudden drop in temperature, and also heavy rain, sometimes with hail, thunder, and lightning.

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What is 0.00550 g converted to mg
Mila [183]

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Explanation:

you have to multiply the mass value by 1000

5 0
3 years ago
Use the periodic table to answer this question. Decomposing calcium carbonate yields calcium oxide and carbon dioxide. What info
erik [133]
This may help you

First write and balance the equation, being: CaCO3 - CaO + CO2 Then, using the periodic table, find the molecular masses of CaCO3 and of CaO, finding their ratio. That will be 100g:56g or 0.1kg:0.056kg. Since you have 4.7kg of CaCO3, it corresponds to Xkg of CaO. Making x the subject, it should be X= 4.7*0.056/100=0,002632

4 0
3 years ago
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A reaction in the laboratory yields 5.98 g KAI(SO2)2, How many moles of potassium aluminum
Ivahew [28]

Answer:

0.0308 mol

Explanation:

In order to convert from grams of any given substance to moles, we need to use its molar mass:

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Now we <u>calculate the number of moles of KAI(SO₂)₂ contained in 5.98 g</u>:

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6 0
3 years ago
What is the mass of a 1.71-l sample of a liquid that has a density of 0.921g/ml?
Temka [501]
Hey there!:

Volume in mL :

1.71 L * 1000 => 1710 mL

Density = 0.921 g/mL

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8 0
3 years ago
How many milliliters of a 3.0 M HCL solution are required to make 250.0 millimeters of 1.2 M HCL?
White raven [17]
The problem above can be solved using M1V1=M2V2  where M1 is the concentration of the concentrated, V1 is the volume of the concentrated solution, M2 is the concentration of the Dilute Solution, V2 is the Volume of the dilute solution. Hence,

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Therefore, you need 100 mL of 3.0 M HCl to form a 250 mL of 1.2 M HCl.
7 0
3 years ago
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