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2 years ago

Note the yellow lines which show attractions between the molecules. Why do you think these attractions occur?

Chemistry

1 answer:

ycow [4]2 years ago

8 0

A hydrogen bond (H-bond) is an example of intermolecular force (IMF).

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True or false <br> The sodium atom becomes a sodium ion with a charge of +1

ddd [48]

Answer:

True

Explanation:

The sodium atom does become a sodium ion with a charge of +1.

6 0

1 year ago

Menstruation occurs on a ______ interval from puberty until menopause

dmitriy555 [2]

D. One Month Interval

8 0

2 years ago

PLEASE ANSWER First get brainly 50 POINTS

Liula [17]

Explanation:

1. photosynthesis

2. Nucleus. The nucleus is the largest and most significant living organelle of the cell. ... Hence it is called brain or control centre of the cell.

3.Cytoplasm

Cells require a thick jelly-like substance that holds organelles in place inside the cell. This substance is known. Cytoplasm. Turgor pressure can help plants move.

4.Chloroplasts absorbing solar energy for cellular activities.

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5 0

3 years ago

Can someone please check k these to see if I have any mistakes

iren [92.7K]

I do not see any mistakes so I think you’re good!

4 0

3 years ago

Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4

inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

$M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol$

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

$M=\frac{n_{solute}}{V_{solution}}$

So you can solve for the moles of the solute:

$n_{solute}=M*V_{solution}$

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

$n_{solute}=1mol/L*1.5L=1.5mol$

But this is just a supposition.

Regards.

4 0

2 years ago