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3 years ago

Help as soon as possible PLEASE!!!

Chemistry

1 answer:

AnnyKZ [126]3 years ago

5 0

(Question 1 points 3).

Food fuel is the fuel in which we use farmland or crops for bio-fuels production to the detriment of the food supply. whereas, mechanical fuel is a material used to produce energy when it is burned. Petroleum products (gasoline, kerosene, and bunker B) are the best being used as a mechanical fuel worldwide.

(Question 2 points 3).

This is because they are lightweight, spread easily, less volatile and are relatively persistent in the environment.

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alukav5142 [94]

Answer:

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Explanation:

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3 years ago

5. The bond in a molecule of Cl2 could be described as

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3 years ago

HNO3 is an Arrhenius ______________ and increases the concentration of __________ when added to water.

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HNO3 and H2SO4 are Arrhenius acids which will increase the concentration of H+ when dissolved in water.

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3 years ago

Calculate the molarity of sodium ion in a solution made

Arada [10]

Answer:

0.1035 M

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Sodium chloride will furnish Sodium ions as:

$NaCl\rightarrow Na^{+}+Cl^-$

Given :

For Sodium chloride :

Molarity = 0.288 M

Volume = 3.58 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 3.58×10⁻³ L

Thus, moles of Sodium furnished by Sodium chloride is same the moles of Sodium chloride as shown below:

$Moles =0.288 \times {3.58\times 10^{-3}}\ moles$

Moles of sodium ions by sodium chloride = 0.00103104 moles

Sodium sulfate will furnish Sodium ions as:

$Na_2SO_4\rightarrow 2Na^{+}+SO_4^{2-}$

Given :

For Sodium sulfate :

Molarity = 0.001 M

Volume = 6.51 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 6.51 ×10⁻³ L

Thus, moles of Sodium furnished by Sodium sulfate is twice the moles of Sodium sulfate as shown below:

$Moles =2\times 0.001 \times {6.51\times 10^{-3}}\ moles$

Moles of sodium ions by Sodium sulfate = 0.00001302 moles

Total moles = 0.00103104 moles + 0.00001302 moles = 0.00104406 moles

Total volume = 3.58 ×10⁻³ L + 6.51 ×10⁻³ L = 10.09 ×10⁻³ L

Concentration of sodium ions is:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity_{Na^+}=\frac{0.00104406}{10.09\times 10^{-3}}$

The final concentration of sodium anion = 0.1035 M

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3 years ago