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babunello [35]
3 years ago
6

When a carousel is in motion, the movement of the carousel horse can best be described as?

Physics
1 answer:
tatiyna3 years ago
5 0
Supposing the carousel is rotating with constant speed, the movement is uniform angular motion.
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Bonus: (It's not that hard, you just have to pay attention to units.) The Saturn V rocket first stage
agasfer [191]

v = 2.45×10^3\:\text{m/s}

Explanation:

Newton's 2nd Law can be expressed in terms of the object's momentum, in this case the expelled exhaust gases, as

F = \dfrac{d{p}}{d{t}} (1)

Assuming that the velocity remains constant then

F = \dfrac{d}{dt}(mv) = v\dfrac{dm}{dt}

Solving for v, we get

v = \dfrac{F}{\left(\frac{dm}{dt}\right)}\;\;\;\;\;\;\;(2)

Before we plug in the given values, we need to convert them first to their appropriate units:

The thrust <em>F</em><em> </em> is

F = 7.5×10^6\:\text{lbs}×\dfrac{4.45\:\text{N}}{1\:\text{lb}} = 3.34×10^7\:\text{N}

The exhaust rate dm/dt is

\dfrac{dm}{dt} = 15\dfrac{T}{s}×\dfrac{2000\:\text{lbs}}{1\:\text{T}}×\dfrac{1\:\text{kg}}{2.2\:\text{lbs}}

\;\;\;\;\;= 1.36×10^4\:\text{kg/s}

Therefore, the velocity at which the exhaust gases exit the engines is

v = \dfrac{F}{\left(\frac{dm}{dt}\right)} = \dfrac{3.34×10^7\:\text{N}}{1.36×10^4\:\text{kg/s}}

\;\;\;= 2.45×10^3\:\text{m/s}

6 0
2 years ago
If a population of 1,000 individuals has 160 rr genotypes, what is the frequency of the rr genotype?
lesya692 [45]
The frequency of a genotype is how often it occurs. This can be obtained by:
number of occurrences / total population
= 160 / 1000
= 0.16 or 16%
7 0
3 years ago
A golf ball (m = 59.2 g) is struck a blow that makes an angle of 50.5 ◦ with the horizontal. The drive lands 130 m away on a fla
fomenos

Answer:

The force is calculated as 338.66 N

Explanation:

We know that force is given by

\overrightarrow{F}=\frac{d\overrightarrow{p}}{dt}=\frac{m(v_{f}-v_{o})}{\Delta t}

We know that range of a projectile is given by

R=\frac{v_{o}^{2}sin(2\theta )}{g}

it is given that R=130 m applying values in the above equation we get

R=\frac{v_{o}^{2}sin(2\theta )}{g}\\\\v_{0}=\sqrt{\frac{Rg}{sin(2\theta )}}\\\\\therefore v_{o}=\sqrt{\frac{130\times 9.81}{sin(2\times 50.5_{o}} )}\\\\v_{o}=36.04m/s

Thus the force is obtained as

\overrightarrow{F}=\frac{d\overrightarrow{p}}{dt}=\frac{59.2\times 10^{}-3(36.04-0)}{6.3\times 10^{-3}}

Thus force equals F=338.66N

4 0
3 years ago
Read 2 more answers
when you park alongside a curb, the front and back wheels must be parallel and no more than ....... inches from the curb
Rainbow [258]

Between 12 to 18 inches.

The front and back wheels must be parallel and within at least 12 to 18 inches of the curb while parking next to a curb on a level street. If there is no curb, park parallel to the road.

➤ The following specific parking guidelines apply to painted colored curbs:

Only stop at a white light long enough to pick up or drop off mail or passengers.

Green-Park only for a short while. For time limits, look for a sign that is put adjacent to the green zone or the time limit that is painted on the curb.

Yellow-Stop for no longer than the indicated amount of time to load or unload cargo or passengers. Noncommercial vehicle drivers are typically expected to stay behind the wheel.

No stopping, standing, or parking is permitted (buses may stop at a red zone marked for buses).

Blue-parking is only allowed for a disabled person or the driver of a disabled person who has a placard or special license plate for disabled people or disabled veterans. A no-parking zone is defined as a crosshatched (diagonal lines) area adjacent to a designated disabled parking space.

Find more on parking related questions at : brainly.in/question/7229826

#SPJ4

7 0
1 year ago
A rectangular block of copper has sides of length 15 cm, 26 cm, and 43 cm. If the block is connected to a 5.0 V source across tw
nexus9112 [7]

Answer:

the case is the one  with the greatest current, L=15 cm ,   i = 2.19 10⁸  A

Explanation:

Ohm's law is

          V = i R

Resistance is

         R = ρ L / A

Where L is the length of the electrons pass and A the area perpendicular to the current

      i = V / R

      i = V (A / ρ L)

      i = V / ρ  (A / L)

We can calculate the relationship between the area and the length to know in which direction the maximum currents

Case 1

      L = 0.15 m

      A = 0.26 0.43 = 0.1118 m2

      A / L = 0.1118 / 0.15

      A / L = 0.7453 m

Case 2

        L = 0.26 m

        A = 0.15 0.43 = 0.0645 m2

        A / L = 0.248 m

Case 3

       L = 0.43 m

       A = 0.15 0.26 = 0.039 m2

        A / L = 0.0907 m

We can see that the case is the one  with the greatest current, L=15 cm

Let's calculate the current

     i = 5 / 1.7 10⁻⁸ (0.7453)

      i = 2.19 10⁸  A

3 0
3 years ago
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