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3 years ago

If the mass of the Jupiter is 1.9*10 kg and radius is fbx loom what is acclerallon due to gravity on the supiter ?

Physics

1 answer:

Bond [772]3 years ago

6 0

Answer:

$g=25.92\ m/s^2$

Explanation:

Given that,

The mass of the Jupiter, $M=1.9\times 10^{27}\ kg$

The radius of Jupiter, $r=69,911\ km=69911\times 10^3 km$

We need to find the acceleration due to gravity on Jupiter. The formula is

$g=G\dfrac{M}{r^2}$

Put all the values,

$g=6.67\times 10^{-11}\times \dfrac{1.9\times 10^{27}}{(69911\times 10^3)^2}\\\\g=25.92\ m/s^2$

So, the value of acceleration due to gravity on the Jupiter is $25.92\ m/s^2$ .

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The mass of a ship before launch is 55,000 metric tons. The ship is launched down a ramp and drops a total of 10 vertical meters

skelet666 [1.2K]

Answer:

ΔT = 17.11 °C

Explanation:

In this case, we have a ship standing on a place with a given mass and it's about to be launched to a lock containing water.

At first, before launch, the ship has a potential energy, and when the ship hits the water after being launched, this potential energy is transformed into kinetic energy.

So, let's calculate first the potential energy of the ship:

E = mgh (1)

We have the mass, gravity and height, so we need to replace the given data here. Before we do that, let's remember to use the correct units. A ton is 1000 kg, so replacing and converting we have:

E = (55000 ton * 1000 kg/ton) * (9.8 m/s²) * 10 m

E = 5.39x10⁹ J

Now this energy will be the same when the ship hits the water, only that is kinetic energy that will result in the rise of temperature. To get this rise we use the following expression:

E = m * C * ΔT (2)

We have the energy, the mass of water (assuming density of water as 1 kg/m³) and the specific heat, so, replacing in (2) and solving for ΔT we have:

ΔT = E / m * C (3)

ΔT = 5.39x10⁹ / 4200 * 75000

Hope this helps

5 0

3 years ago

A 5.0 kg block hangs from the ceiling by a mass-less rope. A Second block with a mass of 10.0 kg is attached to the first block

gayaneshka [121]

The tension in the first and second rope are; 147 Newton and 98 Newton respectively.

Given the data in the question

Mass of first block; $m_1 = 5.0kg$

Mass of second block, $m_2 =10kg$

Tension on first rope; $T_1 =\ ?$

Tension on second rope; $T_2 =\ ?$

To find the Tension in each of the ropes, we make use of the equation from Newton's Second Laws of Motion:

$F = m\ *\ a$

Where F is the force, m is the mass of the object and a is the acceleration ( In this case the block is under gravity. Hence ''a" becomes acceleration due to gravity $g = 9.8m/s^2$ )

For the First Rope

Total mass hanging on it; $m_T = m_1 + m_2 = 5.0kg + 10.0kg = 15.0kg$

So Tension of the rope;

$F = m\ * \ g\\\\F = 15.0kg \ * 9.8m/s^2\\\\F = 147 kg.m/s^2\\\\F = 147N$

Therefore, the tension in the first rope is 147 Newton

For the Second Rope

Since only the block of mass 10kg is hang from the second, the tension in the second rope will be;

$F = m\ * \ g\\\\F = 10.0kg \ * 9.8m/s^2\\\\F = 98 kg.m/s^2\\\\F = 98N$

Therefore, the tension in the second rope is 98 Newton

Learn More, brainly.com/question/18288215

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2 years ago

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Three examples in which velocity is the main factor determining an object's momentum

Lorico [155]

To be honest I’m not sure you might want to ask Newton as he’s an expert best of luck

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When you go camping, you burn wood. Are you contributing to air pollution?

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3 years ago

Are the objects described here in static equilibrium, dynamic equilibrium, or not equilibrium at all? Explain.

Alexandra [31]

Let us examine the given situations one at a time.

Case a. A 200-pound barbell is held over your head.
The barbell is in static equilibrium because it is not moving.
Answer: STATIC EQUILIBRIUM

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The girder is moving, but not accelerating. It is in dynamic equilibrium.
Answer: DYNAMIC EQUILIBRIUM

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The plane is moving at cruising speed, but not accelerating. It is in dynamic equilibrium.
Answer: DYNAMIC EQUILIBRIUM

Case d: A box in the back of a truck doesn't slide as the truck stops.
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3 years ago

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If the mass of the Jupiter is 1.9*10 kg and radius is fbx loom what is acclerallon due to gravity on the supiter ?​

If the mass of the Jupiter is 1.9*10 kg and radius is fbx loom what is acclerallon due to gravity on the supiter ?