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cestrela7 [59]
1 year ago
10

when you park alongside a curb, the front and back wheels must be parallel and no more than ....... inches from the curb

Physics
1 answer:
Rainbow [258]1 year ago
7 0

Between 12 to 18 inches.

The front and back wheels must be parallel and within at least 12 to 18 inches of the curb while parking next to a curb on a level street. If there is no curb, park parallel to the road.

➤ The following specific parking guidelines apply to painted colored curbs:

Only stop at a white light long enough to pick up or drop off mail or passengers.

Green-Park only for a short while. For time limits, look for a sign that is put adjacent to the green zone or the time limit that is painted on the curb.

Yellow-Stop for no longer than the indicated amount of time to load or unload cargo or passengers. Noncommercial vehicle drivers are typically expected to stay behind the wheel.

No stopping, standing, or parking is permitted (buses may stop at a red zone marked for buses).

Blue-parking is only allowed for a disabled person or the driver of a disabled person who has a placard or special license plate for disabled people or disabled veterans. A no-parking zone is defined as a crosshatched (diagonal lines) area adjacent to a designated disabled parking space.

Find more on parking related questions at : brainly.in/question/7229826

#SPJ4

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A lamp is labelled '230 V, 100 W'. How many joules of electrical energy is changed to thermal energy and light if the lamp is sw
viva [34]

Given;

V = 230V

Power, P = 100W

time, t = 2hrs = 7200s

from,

P = IV

and Energy, E= Pt

E = 100*7200

E = 720000 Joules

E = 720KJ

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3 years ago
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Please help with this question ASAP!!!
Paladinen [302]
The answer is the second choice

7 0
4 years ago
Can anyone help me on question 13
Leona [35]

Given that in a parallel circuit:

R1 = 12 ohms

R2= 15 ohms

I = 12 A

I2 = 4 A

V=?

R=?

R3 =?

P=?

Since,

V= IR

or,

V2 = I2 * R2

V2= 4* 15

V2 = 60V

Since in a parallel circuit voltage remain same in all component of the circuit and is equal to the source voltage.

Therefore,

V= V1 = V2 = V3 = 60V

Since,

V= IR

R= V/I

R= 60/12

R= 5 ohm

That is total resistance is equal to 5 ohms.

Since for parallel circuit,

1/R= 1/R1 + 1/R2 + 1/R3

1/5= 1/12+ 1/15 + 1/R3

or

1/R3= 1/5- 1/12- 1/15

1/R3= 1/20

or

R3= 20 ohms

Since,

V=IR

I= V/R

I1= V1/ R1

I1= 60/12

I1= 5 A

I3= V3/R3

I3= 60/20

I3= 3A

Since,

P=VI

P= 60*12

P=  720 watt

P1= V1* I1

P1= 60* 5

P1= 300 watt

P2= V2* I2

P2= 60* 4

P2= 240watt

P3= V3*I3

P3= 60*3

P3= 180 watt

Hence we have,

R1= 12 ohms , R2= 15 ohms, R3= 20 ohms, R= 5 ohms

I1= 5A, I2= 4A, I3= 3A, I= 12 A

V1= V2= V3= V= 60V

P1= 300 watt, P2= 240 watt, P3 = 180 watt, P= 720 watt



6 0
3 years ago
Scientists were studying three different embryos to determine their relationship to humans. The notes about each embryo are show
Sholpan [36]

Answer:

The awnser is B

Explanation:

I took the test.

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4 years ago
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Sam heaves a 16lb shot straight upward, giving it a constant upward acceleration from rest of 35 m/s^2 for 64.0 cm. He releases
makvit [3.9K]

Answer:

6.69 m/s

4.483 m

1.42s

Explanation:

Given that:

Initial Velocity, u = 0

Final velocity, v =?

Acceleration, a = 35m/s²

1.) using the relation :

v² = u² + 2as

v² = 0 + 2(35) * 64*10^-2m

v² = 70 * 0.64

v = sqrt(44.8)

v = 6.693

v = 6.69 m/s

B.) height from the ground, h0 = 2.2

How high ball went , h:

Using :

v² = u² + 2as

Upward motion, g = - ve

0 = 6.69² + 2(-9.8)*(h - 2.2)

0= 6.69² - 19.6(h - 2.2)

44.7561 + 43.12 - 19.6h = 0

19.6h = 44.7561 - 43.12

h = 87.8761 / 19.6

h = 4.483 m

C.)

vt - 0.5gt² = h - h0

6.69t - 0.5(9.8)t²

6.69t - 4.9t² = 1.83 - 2.2

-4.9t² + 6.69t + 0.37 = 0

Using the quadratic equation solver :

Taking the positive root:

1.4185 = 1.42s

5 0
3 years ago
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