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1 year ago

when you park alongside a curb, the front and back wheels must be parallel and no more than ....... inches from the curb

Physics

1 answer:

Rainbow [258]1 year ago

7 0

Between 12 to 18 inches.

The front and back wheels must be parallel and within at least 12 to 18 inches of the curb while parking next to a curb on a level street. If there is no curb, park parallel to the road.

➤ The following specific parking guidelines apply to painted colored curbs:

Only stop at a white light long enough to pick up or drop off mail or passengers.

Green-Park only for a short while. For time limits, look for a sign that is put adjacent to the green zone or the time limit that is painted on the curb.

Yellow-Stop for no longer than the indicated amount of time to load or unload cargo or passengers. Noncommercial vehicle drivers are typically expected to stay behind the wheel.

No stopping, standing, or parking is permitted (buses may stop at a red zone marked for buses).

Blue-parking is only allowed for a disabled person or the driver of a disabled person who has a placard or special license plate for disabled people or disabled veterans. A no-parking zone is defined as a crosshatched (diagonal lines) area adjacent to a designated disabled parking space.

Find more on parking related questions at : brainly.in/question/7229826

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What is a compound formed in protein metabolism and present in much living tissue?

Mamont248 [21]

Answer:

Creatine

It is the compound, formed in protein metabolism and present in much living tissue. It is involved in the supply of energy for muscular contraction.

Creatine improves the strength and increase the lean muscle mass to help the muscles recover more quickly during exercise.

Creatine helps muscle cells to produce more energy. In high intensity exercise, its primary role is to increase the phosphocreatine stores in the muscles.

Creatine is also nitrogenous organic acid that helps in supply of energy in the body. It occurs naturally in meat and fish. It is made by the body. It also obtained by the supplements.

5 0

3 years ago

A 150 g egg is dropped from 3.0 meters. The egg is

Lynna [10]

Answer:

9.2 N, with significant figure rounding (2 s.f.)

Explanation:

This problem can be solved using momentum. The following equation relates momentum (mass & velocity) with force and time:

Note that where v is the final velocity and v₀ is the initial velocity. Δv just means change in velocity.

Mass of the egg is 150 g, but we need to convert to kilograms if we want to use Newtons as a unit. 150 g is equal to 0.15 kg. since 1000 g = 1kg.

m = 0.15 kg

The dropped from 3.0 meters is irrelevant as the question tells us the initial velocity of the egg: 4.4 m/s before it hits the ground.

v₀ = 4.4 m/s [down]

When it comes to a stop, the egg will have a velocity of 0.

v = 0 m/s

The time it takes for the egg to stop is 0.072 seconds.

Δt = 0.072 s

Therefore, if down is positive, then

We round to two significant figures since every quantity has two sig. figs.

We only care about the magnitude, not direction. The answer is 9.2 N.

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5.0

5 0

3 years ago

Kiley, Jermaine, and Gunther are playing tug-of-war. Kiley and Jermaine are on the same side of the rope, and Gunther is on the

Ivanshal [37]

-45N because you add the side together and make it equal 0

8 0

4 years ago

Read 2 more answers

Lightning As a crude model for lightning, consider the ground to be one plate of a parallel-plate capacitor and a cloud at an al

olga nikolaevna [1]

Answer:

$6.67154\times 10^{-9}\ F$

13.009503 C

Explanation:

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

k = Dielectric constant of air $3\times 10^6\ V/m$

Side of plate = 0.7 km

A = Area

d = Distance = 650 m

Capacitance is given by

$C=\dfrac{\epsilon_0A}{d}\\\Rightarrow C=\dfrac{8.85\times 10^{-12}\times 700^2}{650}\\\Rightarrow C=6.67154\times 10^{-9}\ F$

The capacitance is $6.67154\times 10^{-9}\ F$

Electric field is given by

$Q=CV\\\Rightarrow Q=Ckd\\\Rightarrow Q=6.67154\times 10^{-9}\times 3\times 10^6\times 650\\\Rightarrow Q=13.009503\ C$

The charge on the cloud is 13.009503 C

7 0

3 years ago

Part

ArbitrLikvidat [17]

Answer:

Explanation:

the block will move to the right side with small velocity because the force from the left side greater than force from right side. Velocity will be less because of friction and gravitational attraction.

8 0

3 years ago