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kondaur [170]
2 years ago
7

Question 4 (1 point)

Physics
1 answer:
irga5000 [103]2 years ago
6 0

Answer:

ω₁ = 8 rad/s

Explanation:

Assuming

1) the clay sticks to the disc we can apply conservation of angular momentum

2) That the disc moment of inertia is 1.5 kg•m²

Initial angular momentum = L = I₀ω₀ = 1.5(14) = 21 kg•m²/s

After the clay joins the party, the moment of inertia is

I₁ = 1.5 + 0.5(1.5²) = 2.625 kg•m²

21 = 2.625ω₁

ω₁ = 8 rad/s

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ohaa [14]

the answer is concave lens

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a 100 g cart initially moving at 0.5 m/s collides elastically from a stationary 180 g cart. a) using the equation in the theory,
cupoosta [38]

A 100 g cart is moving at 0.5 m/s that collides elastically from a stationary 180 g cart. Final velocity is calculated to be 0.25m/s.

Collision in which there is no net loss in kinetic energy in the system as a result of the collision is known as elastic collision . Momentum and kinetic energy both are conserved quantities in elastic collisions.

Collision in which part of the kinetic energy is changed to some other form of energy is inelastic collision.

For an elastic collision, we use the formula,

m₁V₁i+ m₂V₂i = m₁V1f + m₂V₂f

For a perfectly elastic collision, the final velocity of the 100g cart will each be 1/2 the velocity of the initial velocity of the moving cart.

Final velocity = 0.5/2

=0.25 m/s.

To know more about elastic collision, refer

brainly.com/question/7694106

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7 0
1 year ago
The diameter of the moon is a little less than the distance across the United States. Please select the best answer from the cho
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Answer:

true

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6 0
3 years ago
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A child whirls a 3.00 kg ball on a string .50 m from the axis of rotation in a horizontal circle. The ball makes 1 revolution in
melamori03 [73]

Answers:

a) 0.5 m/s^{2}

b) 1.5 N

Explanation:

a) The centripetal acceleration a_{c} of an object moving in a uniform circular motion is given by the following equation:  

a_{c}=\omega^{2} r  

Where:

\omega=1 \frac{rev}{s} is the angular velocity of the ball

r=0.5 m is the radius of the circular motion, which is equal to the length of the string

Then:

a_{c}=(1 \frac{rev}{s})^{2} 0.5 m  

a_{c}=0.5 m/s^{2} This is the centripetal acceleration of the ball

b) On the other hand, in this circular motion there is a force (centripetal force F) that is directed towards the center and is equal to the tension (T) in the string:

F=T=m. a_{c}

Where m=3 kg is the mass of the ball

Hence:

T=(3 kg)(0.5 m/s^{2})

T=1.5 N This is the tension in the string

7 0
3 years ago
How many electrons would it take to equal the mass of a proton? Use two significant figures.
mezya [45]
<span>How many electrons would it take to equal the mass of a proton:
Here's one way of finding the value of it:
=> number of electrons is equivalent to 1 proton.
Let's have an example.
1.6726*10 -24g
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Based on the given example above, the electrons is 1 839 per 1 proton.
It's about 1800 electrons/proton.</span>
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3 years ago
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