Answer:
222.30 L
Explanation:
We'll begin by calculating the number of mole in 100 g of ammonia (NH₃). This can be obtained as follow:
Mass of NH₃ = 100 g
Molar mass of NH₃ = 14 + (3×1)
= 14 + 3
= 17 g/mol
Mole of NH₃ =?
Mole = mass /molar mass
Mole of NH₃ = 100 / 17
Mole of NH₃ = 5.88 moles
Next, we shall determine the number of mole of Hydrogen needed to produce 5.88 moles of NH₃. This can be obtained as follow:
N₂ + 3H₂ —> 2NH₃
From the balanced equation above,
3 moles of H₂ reacted to produce 2 moles NH₃.
Therefore, Xmol of H₂ is required to p 5.88 moles of NH₃ i.e
Xmol of H₂ = (3 × 5.88)/2
Xmol of H₂ = 8.82 moles
Finally, we shall determine the volume (in litre) of Hydrogen needed to produce 100 g (i.e 5.88 moles) of NH₃. This can be obtained as follow:
Pressure (P) = 95 KPa
Temperature (T) = 15 °C = 15 + 273 = 288 K
Number of mole of H₂ (n) = 8.82 moles
Gas constant (R) = 8.314 KPa.L/Kmol
Volume (V) =?
PV = nRT
95 × V = 8.82 × 8.314 × 288
95 × V = 21118.89024
Divide both side by 95
V = 21118.89024 / 95
V = 222.30 L
Thus the volume of Hydrogen needed for the reaction is 222.30 L
Answer:
1.49×10²² atoms of H are contained in the sample
Explanation:
TNT → C₇H₅N₃O₆
1 mol of this has 7 moles of C, 5 moles of H, 3 moles of N and 6 moles of O
Let's determine the mass of TNT.
Molar mass is = 227 g/mol
As 1 mol has (6.02×10²³) NA atoms, how many moles are 8.94×10²¹ atoms.
8.94×10²¹ atoms / NA = 0.0148 moles
So this would be the rule of three to determine the mass of TNT
3 moles of N are in 227 g of compound
0.0148 moles of N are contained in (0.0148 .227) / 3 = 1.12 g
Now we can work with the hydrogen.
227 grams of TNT contain 5 moles of H
1.12 grams of TNT would contain (1.12 .5) / 227 = 0.0247 moles
Finally let's convert this moles to atoms:
0.0247 mol . 6.02×10²³ atoms / 1 mol = 1.49×10²² atoms
The grams of carbon dioxide that are in 35.6 liters of Co2 is calculates as below
calculate the number of moles of CO2
At STP 1 mole = 22.4 L
what about 35.6 liters
= 1mole x 35.6 liters/ 22.4 liters = 1.589 moles
mass of CO2 = moles x molar mass of CO2
= 1.589 mol x 44 g/mol = 69.92 grams
Answer:
3–methyl–2–butanol
Explanation:
To name the compound, we must:
1. Identify the functional group.
2. Give the functional group of the compound the lowest possible count.
3. Locate the longest continuous carbon chain. This gives the parent name of the compound.
4. Identify the substituent group attached.
5. Give the substituent group the lowest possible count.
6. Combine the above to get the name of the compound.
Now, let us obtain the name of the compound.
1. The functional group of the compound is Alcohol i.e —OH.
2. The functional group is located at carbon 2.
3. The longest continuous carbon chain is carbon 4 i.e butane. But the presence of the functional group i.e OH will replace the –e in butane with –ol. Therefore, the compound is butanol.
4. The substituent group attached is methyl i.e CH3.
5. The substituent group is located at carbon 3.
6. Therefore, the name of the compound is:
3–methyl–2–butanol.
Answer:
The pH of a solution with the [H + ] = 1 × 10 -2 M is 2 and the pH of a solution with the [H + ] = 1 × 10 -10 M is 10. ( I think this is correct ).
Explanation:
