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2 years ago

What are 3 general rules to predict the stability of an isotope

1 answer:

8 0

1) Calculate the total number of nucleons (protons and neutrons) in the nuclide
--> If the number of nucleons is even, there is a good chance it is stable.

2) Are there a magic number of protons or neutrons?
--> 2,8,20,28,50,82,114 (protons), 126 (neutrons), 184 (neutrons) are particularly stable in nuclei.

3) Calculate the N/Z ratio.
--> Use the belt of stability (Figure 1) to determine the best way to get from an unstable nucleus to a stable nucleus

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Does anyone know what order?

mamaluj [8]

I believe it is decomposition, neutralization, combustion

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3 years ago

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Which of the following correctly describes one way that photosynthetic plants are involved in the carbon cycle? Choose 1 answer:

brilliants [131]

Answer:

The correct answer is - (Choice A) A Photosynthetic plants can move carbon from the atmosphere into an ecosystem’s food web.

Explanation:

Photosynthesis is the process performed by photosynthetic or green plants in presence of light atmospheric carbon dioxide and water converted into glucose (6 carbon compound) and oxygen.

This glucose or sugar is utilized by the plants that are producers in the ecosystem food web. These producers are fed by consumers and carbon molecules transfer from all the trophic levels in the food chain or food web in the process.

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3 years ago

A gas at a constant volume has an initial temperature of 300.0 K and an initial pressure of 10.0 atm. What pressure does the gas

harkovskaia [24]

$\frac{500}{300} times 10=16.667 atm$

4 0

2 years ago

A 0.1326 g sample of magnesium was burned in an oxygen bomb calorimeter. the total heat capacity of the calorimeter plus water w

Sladkaya [172]

Answer: Th enthalpy of combustion for the given reaction is 594.244 kJ/mol

Explanation: Enthalpy of combustion is defined as the decomposition of a substance in the presence of oxygen gas.

W are given a chemical reaction:

$Mg(s)+\frac{1}{2}O_2(g)\rightarrow MgO(s)$

$c=5760J/^oC$

$\Delta T=0.570^oC$

To calculate the enthalpy change, we use the formula:

$\Delta H=c\Delta T\\\\\Delta H=5760J/^oC\times 0.570^oC=3283.2J$

This is the amount of energy released when 0.1326 grams of sample was burned.

So, energy released when 1 gram of sample was burned is = $\frac{3283.2J}{0.1326g}=24760.181J/g$

Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:

$\Delta H=24760.181J/g\times 24g/mol\\\\\Delta H=594244.3J/mol\\\\\Delta H=594.244kJ/mol$

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3 years ago

Regulations on air pollutants in the United States and other countries since the 1970s have greatly reduced the amount of CO2 em

Lynna [10]

True.

Because some people breathe less pollution and face lower risks of premature death and other serious health

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2 years ago

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