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Sedaia [141]
3 years ago
8

Neptunium's only naturally occurring isotope, 23793np, decays by emitting one alpha particle, one beta particle, and one gamma r

ay. What is the new atom formed from this decay?
Chemistry
1 answer:
Olin [163]3 years ago
5 0

The given isotope of Neptunium is ^{237} _{93} Np

Alpha decay of an isotope results in daughter nuclide with mass number less by 4 units and atomic number less by 2 units than the parent isotope.

Alpha decay of Neptunium-237 can be represented as:

^{237} _{93} Np-->^{233}_{91} Pa+^{4} _{2} He

Beta decay of the above formed protactinium nuclide can be represented as:

^{233}_{91}Pa-->^{233} _{92} U+^{0}_{-1}e

Gamma decay releases only energy in the form of gamma rays, the nuclide remains the same.

^{233}_{92}U-->^{233}_{92}U+γ

The new atom formed after the given decays is ^{233}_{92}U

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