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Rudik [331]
3 years ago
12

Rewrite each equation below. Then solve your new equation. Be sure to check your solution using the original equation.

Mathematics
1 answer:
natali 33 [55]3 years ago
8 0
The answer is on the paper

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Circle the reason for each of the following manipulations used to simplify the product (8x^2) (3x^7) ?
gayaneshka [121]

Answer:

fgd

Step-by-step explanation:

3 0
3 years ago
Please help me <br><br> Write the 2 hundreds each number is between
Ede4ka [16]

53: 800 and 900

54: 700 and 800

55: 500 and 600

56: 2,771,100 and 2,771,200

57: 90,120,000 and 90,120,100

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4 0
4 years ago
What is the equation of the circle shown in the graph?<br> 6 9 12 36
Naddika [18.5K]
You need to add a picture in order for others to understand what you are referring to.
4 0
3 years ago
Anybody know the correct answer?
earnstyle [38]

Since \csc^2{x}=\frac{1}{\sin^2{x}} and \cot^2{x}=\frac{\cos^2{x}}{\sin^2{x}}, we can rewrite the right side of the equation as

\frac{1}{\sin^2{x}}-\frac{\cos^2{x}}{\sin^2{x}} =\frac{1-\cos^2{x}}{\sin^2{x}}

Using the identity \sin^2{x}+\cos^2{x}=1, we can subtract \cos^2{x} from either side to obtain the identity \sin^2{x}=1-\cos^2{x}

substituting that into our previous expression, the right side of our equation simply becomes

\frac{\sin^2{x}}{\sin^2{x}}=1

We can now write our whole equation as

3\tan^2{x}-2=1

Adding 2 to both sides:

3\tan^2{x}=3

dividing both sides by 3:

\tan^2{x}=1

\tan{x}=\pm1

When 0 ≤ x ≤ π, tan x can only be equal to 1 when sin x = cos x, which happens at x = π/4, and it can only be equal to -1 when -sin x = cos x, which happens at x = 3π/4

4 0
3 years ago
PLS HELP ME ASAP!!!!!!!!!!!!!!
Anton [14]
The answer to that question is C
8 0
3 years ago
Read 2 more answers
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