<span>If one of the impurities in diesel fuel has the formula c2h6s, then the products that will form would be carbon dioxide, water and sulfur dioxide. The balanced chemical reaction would be as follows:
</span>C2H6S(l)<span> + 9/2O2(g) = 2CO2(g) + 3H2O(v) + SO2(g)
</span>
Hope this answers the question.
Answer:
Explanation:
Combustion reaction is given below,
C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)
Provided that such a combustion has a normal enthalpy,
ΔH°rxn = -1270 kJ/mol
That would be 1 mol reacting to release of ethanol,
⇒ -1270 kJ of heat
Now,
0.383 Ethanol mol responds to release or unlock,
(c) Determine the final temperature of the air in the room after the combustion.
Given that :
specific heat c = 1.005 J/(g. °C)
m = 5.56 ×10⁴ g
Using the relation:
q = mcΔT
- 486.34 = 5.56 ×10⁴ × 1.005 × ΔT
ΔT= (486.34 × 1000 )/5.56×10⁴ × 1.005
ΔT= 836.88 °C
ΔT= T₂ - T₁
T₂ = ΔT + T₁
T₂ = 836.88 °C + 21.7°C
T₂ = 858.58 °C
Therefore, the final temperature of the air in the room after combustion is 858.58 °C
For sig figs, you count the total number of numbers that aren’t 0, you only count 0 if they are after a decimal point. since there is not a decimal point, there are 2 significant figures, answer A
Doesnt the number of carbon atoms stay the same.
Though the weight of carbon in 1.5g is 1.24g.
This is because the RAM of C4 is 48.
The RFM of C4H10 is 58. Therefore, 48/58 is carbon in butane.
48/58 x 1.5 = 1.24g
Answer:
This question is incomplete
Explanation:
This question is incomplete but one can assume the answer from the definition of quantum mechanics. Quantum mechanics is the science that describes particles in nature at the atomic and subatomic particle (electron, proton and neutron) level. Thus it can be assumed that atoms and subatomic particles are used to broadly describe particles.