Answer:
10.4664 grams of CO
Explanation:
Remark
There's a couple of things you must look out for in this question.
1. The use of the term atoms. There are 2 atoms in each mol of CO
2. You need to divide by 2 to find the number of molecules which will lead to moles.
<u>Step one</u>
Divide the number of atoms by 2
4.50 e^23 / 2 atoms = 2.25 * 10^23 molecules.
<u>Step Two</u>
Find the number of moles of CO
1 mol of anything is 6.02 * 10^23 molecules in this case
x = 2.25 * 10^23 molecules
1/x = 6.02 * 10^23/2.25 * 10 ^23 Cross multiply
1 * 2.25 * 10^23 = 6.02*10^23 * x Divide by 6.02 * 10^23
2.25 * 10 ^ 23 / 6.02 * 10^23 = x
x = .3738 moles of CO
<u>Step Three</u>
Find the gram molecular mass of CO
C = 12
O = 16
1 mole = 12 + 16 = 28 grams.
<u>Step Four</u>
Find the number of gram in 0.3738 mols
1 mol = 28 grams
0.3738 mol = x Cross multiply
x = 28 * 0.3738
x = 10.4664 grams
Answer:
A heating curve graphically represents the phase transitions that a substance undergoes as heat is added to it. The plateaus on the curve mark the phase changes. The temperature remains constant during these phase transitions.
Main Answer:
Given data:
Initial Pressure P1 = 570 mm hg
Initial Volume V1 = 2270 ml
Final Pressure P2 = ? mm hg
Final Volume V1 = 1250 ml
According to the ideal gas equation,
PV = constant.
P1V1 = P2V2
P2 = P1V1/V2
P2 = (570 x 2270) / 1250
P2 = 1035.12 mm hg
The final pressure at volume of 1250 ml is 1035.12 mm hg.
Explanation:
What is ideal gas equation ?
The ideal gas equation is as follows:
PV = nRT
where P = Pressure
V = Volume
n = number of moles of gas
R = Universal gas constant
T = Temperature
This ideal gas equation provides the macroscopic particles behavior of the gas. At this condition, the particles of the gas, won't be attract or repel each other. It is consider as the stable condition.
To know more about ideal gas equation, please visit:
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For example, silicon has 14 protons and 14 neutrons. Its atomic number is 14 and its atomic mass is 28.
Answer:
Below.
Explanation:
1. Al2(SO4)^3 (aq) + 6LiOH aql) ----> 3Li2SO4 (aq) + 2Al(OH)^3 (s)
2. (NH4)2CO3 (aq) + MgCl2 (aq) ----> 2(NH4)Cl (aq) + MgCO3 (s).