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4 years ago

What discovery led J.J. Thomson to decide that atoms were not indivisible, but are actually composed of smaller parts?

1 answer:

7 0

Thomson used a beam of negatively charged particles. Using a beam of particles and detecting the scattering of the particles after they hit gold foil.

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The total volume of a soda can is 415 mL. Of this 415 mL, there is 60.0 mL of headspace(empty space aka volume) for the CO2 gas

almond37 [142]

Answer:

gay

Explanation:

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3 years ago

Which substances are most likely acids? Check all that apply. CH4, HI, NH3, HNO3, NaCI

rosijanka [135]

Answer is: CH4 and NaCI hope this helps you

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3 years ago

If a 185-lb patient is prescribed 145mg. What dosage is the patient receiving in mg/kg of his body weight?

Anestetic [448]

Answer:

1.728 mg/kg

Explanation:

First have to convert the patient's weight to kg

1 lb = 0.454 kg

185 lb in kg = 83.9 kg

Then we have to divide the dose per the weight of the patient

145 mg for 83.9 kg = 145/83.9

= 1.728 mg/kg

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4 years ago

Air, with an initial absolute humidity of 0.016 kg water per kg dry air, is to be dehumidified for a drying process by an air co

amid [387]

Answer:

(a) The proportion of dry air bypassing the unit is 14.3%.

(b) The mass of water removed is 1.2 kg per 100 kg of dry air.

Explanation:

We can express the proportion of air that goes trough the air conditioning unit as $p_{d}$ and the proportion of air that is by-passed as $p_{bp}$ , being $p_{d}+p_{bp}=1$ .

The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:

$0.004 = 0.016*p_{bp}+ 0.002*p_{d}$

Replacing the first equation in the second one we have

$0.004 = 0.016*(1-p_{d})+ 0.002*p_{d}=0.016-0.016*p_{d}+0.002*p_{d}\\0.004 - 0.016 = (-0.016+0.002)*p_{d}\\-0.012 = -0.014*p_{d}\\p_{d}=\frac{-0.012}{-0.014}=0.857\\\\p_{bp}=1-p_{d}=1-0.857=0.143$

(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.

It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.

The water removed of every 100 kg of dry air is

$100 kgDA*0.857*0.014 kgW/kgDA= 1.1998 \approx 1.2 kgW$

It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).

100 * 0.012 = 1.2 kgW

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4 years ago

For each pair, which has higher potential energy?

Allushta [10]

Answer:

Maybe A)

Explanation:

Can you make me the Brainliest answer ?

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3 years ago