Answer:
Option D. 400 mmHg
Explanation:
The following data were obtained from the question:
Mole of He (nHe) = 0.04 mole
Mole of Ne (nNe) = 0.06 mole
Total pressure = 10³ mmHg
Partial pressure of He =.?
Next, we shall determine the total number of mole in the reaction vessel.
This can be obtained as follow:
Mole of He (nHe) = 0.04 mole
Mole of Ne (nNe) = 0.06 mole
Total mole =?
Total mole = nHe + nNe
Total mole = 0.04 + 0.06
Total mole = 0.1
Next, we shall determine the mole fraction of He.
This can be obtained as follow:
Mole fraction = mole of gas /total mole
Mole of He (nHe) = 0.04 mole
Total mole = 0.1
Mole fraction of He =.?
Mole fraction of He = nHe/total mole
Mole fraction of He = 0.04/0.1
Mole fraction of He = 0.4
Finally, we shall determine the partial pressure of He as follow:
Partial pressure = mole fraction x total pressure
Mole fraction of He = 0.4
Total pressure = 10³ mmHg
Partial pressure of He =.?
Partial pressure of He = 0.4 x 10³
Partial pressure of He = 400 mmHg.
Therefore, the partial pressure of He is 400 mmHg.
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