All categories

2 years ago

1. Which statements about activation energy are true? Select all that apply.

Chemistry

1 answer:

Nookie1986 [14]2 years ago

3 0

The true statements about activation energy are as follows:

Activation energy is the minimum quantity of energy that the reactants must possess in order to undergo a specified reaction.
Activation energy is determined by the strength of the bonds that must be broken.

<h3>What is activation energy?</h3>

Activation energy is the minimum amount of energy that reactants in a chemical reaction must possess so as to get converted into products.

In a chemical reaction, reactants form products, hence, certain bonds must be broken in the reactant molecules to form the products.

The energy needed to break the bonds of the reactants is known as activation energy.

Therefore, the true statements about activation energy are as follows:

Activation energy is the minimum quantity of energy that the reactants must possess in order to undergo a specified reaction.
Activation energy is determined by the strength of the bonds that must be broken.

Learn more about activation energy at: brainly.com/question/11334504

You might be interested in

How many grams and what is the limiting reactent?

gayaneshka [121]

Hello!

1) What is the limiting reactant?

The chemical equation for this reaction is:

2Al(OH)₃ → Al₂O₃ + 3H₂O

The Limiting Reactant is the one that is in the lowest amount in the reaction and determines how many moles are produced. You can see that in this chemical equation there is only one reactant since this reaction is a decomposition reaction. So, the limiting reactant is Al(OH)₃.

2) How many grams of water are produced?

The chemical equation for this reaction is:

2Al(OH)₃ → Al₂O₃ + 3H₂O

So, we are going to use the following conversion factor to go from grams of Al(OH)₃ to grams of water:

$17,8 g Al(OH)_3* \frac{1 mol Al(OH)_3}{78 g Al(OH)_3}* \frac{3 moles H_2O}{2 moles Al(OH)_3}* \frac{18,015 g H_2O}{1 mol H_2O} \\ =6,17 g H_2O$

So, 6,17 grams of Water are produced.

Have a nice day!

5 0

4 years ago

What is the freezing point in °C) of a 0.195 m

Elina [12.6K]

Answer:

$T_S=-1.09\°C$

Explanation:

Hello!

In this case, since the freezing point depression for a solution is computed via:

$(T_S-T_W)=-imK_f$

Whereas TW is the freezing temperature of water, TS that of the solution, i the van't Hoff's factor (3 for K2S as it ionizes properly), m the molality of the solution and Kf the freezing point constant of water. Thus, we plug in to obtain:

$(T_S-0\°C)=-3*0.195m*1.86\frac{\°C}{m}\\\\T_S=-1.09\°C$

Best regards!

4 0

4 years ago

Read 2 more answers

What is the main cause of increased erosion

anyanavicka [17]

The main cause of increased erosion is natural elements like rain, wind and ice. Erosion is the process by which the surface of the Earth gets worn down.
Soil erosion is also a big thing, it is caused by mostly rain that contributes to floods. This stuff is bad for farmers because they do a lot of farming and with erosion increasing the growing crops are decreasing because of erosion.

6 0

3 years ago

In which of these samples do the molecules most likely have the most kinetic energy?

hichkok12 [17]

Answer:

water vapor

Explanation:

8 0

3 years ago

Calculate the theoretical density (in g/cm3) of copper (Cu), given that it has the FCC structure. The atomic weight of Cu is 63.

sasho [114]

Answer:

8.937g/cm³

Explanation:

To answer this question we need to know that, in 1 unit FCC cell you have:

Edge length = √8 * R

<em>Volume = 8√8 * R³</em>

<em>And there are 4 atoms per unit cell</em>

<em />

<em>Mass of 4 atoms in g:</em>

4 atom * (1mol / 6.022x10²³atom) * (63.55g / mol) = 4.221x10⁻²²g

<em />

<em>Volume in cm³:</em>

0.1278nm * (1x10⁻⁷cm / 1nm) = 1.278x10⁻⁸cm

Volume = 8√8 * (1.278x10⁻⁸cm)³

Volume = 4.723x10⁻²³cm³

And density is:

4.221x10⁻²²g / 4.723x10⁻²³cm³ =

6 0

4 years ago