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Elan Coil [88]
3 years ago
12

2. When you transfer energy into a substance, the molecules' kinetic energy

Chemistry
1 answer:
GenaCL600 [577]3 years ago
8 0
I don’t! Know bit I guess it’s C
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How much energy must a 10 gram block of ice gain in order to melt ?
Minchanka [31]

Answer:

the answer is 10 times

Explanation:

because it takes 10 times as much energy -3330 j - to melt 10.0 grams of ice.

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2 years ago
How maby electrons fill an orbit
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Each can hold two electrons
5 0
4 years ago
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Enter an equation for the formation of NO2(g) from its elements in their standard states. Express your answer as a chemical equa
kkurt [141]

The standard state of the elements Nitrogen and Oxygen are N2 and O2, knowing that they are diatomic elements. With that piece of information, the unbalanced equation for the formulation of NO2(g) should be as follows -

N2 + O2 ---> NO2

And if you include their states -

N2 ( g ) + O2 ( g ) ---> NO2 ( g )

To balance this chemical equation consider the number of reactants and products on other side of the equation. If you were to include a coefficient of one - half with respect to N2 on the reactant side, it would balance the reactants and products -

7 0
3 years ago
Which of the following would increase the amount to dissolve a solid solute?
AVprozaik [17]

By stirring and increasing temperature, there is an increase in dissolving capacity of the solid solute.

<u>Explanation:</u>

If a solute is added to the solution, it doesn't get dissolve easily then we have to increase the temperature, which in turn increases the movement of the solvent (may be water) and the solute particles, thus increases the dissolving power of the solid solute. One more way is by constant stirring, that is by making more contact among the solvent as well as the solute particles there by increasing the solubility of solid solute.

5 0
3 years ago
Write the Henderson-Hasselbalch equation for a propanoic acid solution (CH3CH2CO2H, pKa = 4.874) using the symbols HA and A–, an
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The Henderson-Hasselbalch approximation is for conjugate acid-base pairs in a buffered solution. We're going to call HA a weak acid, and A- its conjugate base. The equation is as follows:
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Plugging in our symbols and the pKa value, the equation becomes:
pH = 4.874 + log([A-]/[HA])
7 0
3 years ago
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