The domain of a function are its possible input values
The domain of the function is <em>(b) all real numbers greater than or equal to 0.</em>
From the graph, we have the following observations
- <em>t represents time (it is plotted on the x-axis)</em>
- <em>t starts at 0</em>
- <em>t has no end</em>
The above observations imply that; the domain starts from 0
Hence, the domain of the function is the set of all real numbers greater than or equal to 0.
Read more about domain at:
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We know that
<span>ρ = density of gasoline = 737 kg/m³ (at T = 60°F = 15.6°C)
</span>ρ = m/V
ρV = m
V = m/ρ
V = 49.0 kg / 737 kg/m³
<span>V = 0.066 m³
[volume of the tank]=L*W*H-----> H=volume/[L*W]----> H=0.066/(0.9*0.4)
H=0.1833 m
the answer is
t</span><span>he depth of the tank is 0.18 m</span>
The length is 2.4
1.2 times 2 to take away the both width sides
minutes 2.4 from 7.2 you get 4.8 then divide by two because it’s a rectangle it has to length side and you get 2.4
A)
Let x represent the cost of 1 student, and y the cost of 1 teacher.
B)
In the first group, there's 25 students and 2 teachers. Their total cost is $97.50
So 25x + 2y = 97.50
In the second group, there's 32 students and 3 teachers. Their total cost is $127
So 32x + 3y = 127
We get the following system of equations:
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)
C)
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)
In equation (1)
25x + 2y = 97.50
25x + 2y - 2y = 97.50 - 2y
25x = 97.50 - 2y
25x / 25 = 97.50/25 - 2y/25
x = 3.9 - (2/25)y
In equation (2), let's replace x by its algebraic value
32x + 3y = 127
32(-2/25y + 3.9) + 3y = 127
11/25y + 124.8 = 127
11/25y + 124.8 - 124.8 = 127 - 124.8
11/25y = 2.2
(11/25y) / (11/25) = 2.2 / (11/25)
y = 5
x = -2/25y + 3.9
x = -2/25 * 5 + 3.9
x = 3.5
So the cost of each student is $3.5, and the cost of each teacher is $5.
Hope this helps! :)
Answer:
The balance after 1 year is;
$1,014.05
Step-by-step explanation:
To do this, we use the compound interest formula
That will be ;
A =P (1 + r/n)^nt
A is the amount generated which we want to calculate
r is the rate = 1.4% = 0.014
P is the amount deposited = $1,000
n is the number of times it is compounded annually which is 2 (semi-annually means 2 times in a year)
this the number of years which is 1
we have this as:
A = 1,000( 1 + 0.014/2)^(2*1)
A = 1,000(1 + 0.007)^2
A = 1,000(1.007)^2
A = $1,014.05
