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Sunny_sXe [5.5K]
3 years ago
13

Can someone please help me solve. like now? or in a few minutes tops

Physics
2 answers:
LenKa [72]3 years ago
7 0

Explanation:

Hunk

s=540 km, v=90km/hr t=540/9= 6hrs

Tim completed the same journey 1hr30min less than Hunk

Tim's t= 6 - 1.5 = 4.5hrs

av speed = total dist/time taken

= 540/4.5

= 120km/hr

Goodluck

mafiozo [28]3 years ago
6 0
Hmmmm...I’m not sure but you will will get the right answer don’t give up!
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The greatest height reported for a jump into an airbag is 99.4 m by stuntman Dan Koko. In 1948 he jumped from rest from the top
vaieri [72.5K]

Answer:

v = 44,16 m/s

Explanation:

We will fixate our reference in the starting point from where Dan jumped of, at the top of the Casino. Therefore, the displacement made when dan reached the airbag would be of y= -99,4 m viewed from our reference. We describe the motion of dan with the equation:

v_y^2 =v_0^2 +2ay

Dan jumped from the rest, that means that the initial velocity v_0=0, therefore:

 v_y^2 =2ay \rightarrow v_y = \sqrt{2ay}

Since Dan is moving in the negative axis regarding our reference point, we take the negative root of the equation.

v_y=-√(2*(-9,81 m/s^2 )*(-99,4 m) )=44,1613 m/s  v_y =- \sqrt{2*(-9,81 m/s^2)*(-99,4 m)} = 44,1613 m

So, if we don’t take the air resistance into account, Dan would have achieved an velocity of 44,16 m/s when he reached the airbag.

I hope everything was clear with my explanation. If you need anything else, let me know. Have a great day :D

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3 years ago
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3 years ago
Can anyone answer this for my friend course I am not sure of what I did I don’t take physics but I did it
kogti [31]

Answer:

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Explanation:

because if you divide 110 by 40 you get 2.75

3 0
3 years ago
Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end
ozzi

Answer:

The total work that the rope does to Mangnus is - 5780 Jules.

Explanation:

By definition, the work is defined as:

W=F.d

Where F and d are the force and the total displacement. Note that in the definition the product is a scalar product since F and d are both vectors.  

Take into account that according to third Newton's law the force that the rope does to Magnus is opposite to the force that Magnus does to the rope, therefore the scalar product will be negative due the rope's force goes against to Magnus displacement.  

For calculating the work, we take 2500 N as the value for the force and 2.312 meters as the value for the displacement:

W=-2500 N * 2.312 m

W=-5780 Nm = -5780 J

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