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Sunny_sXe [5.5K]
3 years ago
13

Can someone please help me solve. like now? or in a few minutes tops

Physics
2 answers:
LenKa [72]3 years ago
7 0

Explanation:

Hunk

s=540 km, v=90km/hr t=540/9= 6hrs

Tim completed the same journey 1hr30min less than Hunk

Tim's t= 6 - 1.5 = 4.5hrs

av speed = total dist/time taken

= 540/4.5

= 120km/hr

Goodluck

mafiozo [28]3 years ago
6 0
Hmmmm...I’m not sure but you will will get the right answer don’t give up!
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Hi! I'm a few days late since I just saw this question just now, but I'll answer anyway.

Answer:

When an unbalanced force acts on a moving object, the velocity of the object will change. Change in velocity means a change in speed, direction, or both. For example, if you kick a soccer ball and it moves from one place to another, it means that unbalanced forces are acting upon it. The ball moves from one place to another after kicking it so the position changed.

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The gravitational force of attraction be-
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Answer:

2.15 m

Explanation:

Newton's Law of Universal Gravitation:

\displaystyle F_g = G \frac{m_1 m_2}{r^2}  

  • \displaystyle F_g is the gravitational force of attraction
  • \displaystyle G is the universal gravitational constant
  • m_1 and m_2 are the two masses of the two objects
  • \displaystyle r is the distance between the centers of the two objects.

List the known values:

  • \displaystyle F_g = 3.47 \cdot 10^-^8 \ \text{N}  
  • \displaystyle G = 6.673 \cdot 10^-^1^1 \ \frac{Nm^2}{kg^2}
  • \displaystyle m_1 = 44.8 \ \text{kg} \\ m_2 = 53.9 \ \text{kg}
  • \displaystyle r =\ ?

Plug these values into the equation:

  • \displaystyle 3.47 \cdot 10^-^8 \ \text{N} = 6.673 \cdot 10^-^1^1 \ \frac{Nm^2}{kg^2} \frac{(44.8 \ \text{kg})(53.9 \ \text{kg})}{r^2}

Notice that the units \displaystyle \text{N}, \displaystyle \text{kg}^2, and \displaystyle \text{m} cancel out. We are left with the unit \displaystyle \text{m} for radius r.

Get rid of the units to make the problem easier to read.

  • \displaystyle 3.47 \cdot 10^-^8= 6.673 \cdot 10^-^1^1 \ \frac{(44.8)(53.9) \ }{r^2}  

Multiply the masses together.

  • \displaystyle 3.47 \cdot 10^-^8= 6.673 \cdot 10^-^1^1 \ \frac{(2414.72)}{r^2}

Multiply the gravitational constant and the masses together.

  • \displaystyle 3.47 \cdot 10^-^8= \frac{1.61134265\cdot 10^-^7}{r^2}

Solve for r^2 by dividing both sides by 3.47 * 10^(-8) and moving r^2 to the left.

  • \displaystyle r^2 = \frac{1.61134265\cdot 10^-^7}{3.47\cdot 10^-^8}
  • r^2 = 4.64363876

Take the square root of both sides.

  • r=2.154910383  

The students are sitting about 2.15 m apart from each other.

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Answer:

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r=0.292*(8.45)^2/78.9

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