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kolbaska11 [484]
3 years ago
5

Which of the following is the most likely end for a star that is small to average in size? A. blue main sequence B. red supergia

nt C. supernova D. white dwarf
Physics
2 answers:
likoan [24]3 years ago
7 0
"White dwarf" is the one among the following choices given in the question that is <span>the most likely end for a star that is small to average in size. The correct option among all the options that are given in the question is the last option or option "D". I hope that this is the answer that has actually helped you.</span>
stiv31 [10]3 years ago
3 0

Answer: D. White Dwarf

Explanation:

A star has life-cycle similar to any living specie. A star takes birth, goes through main sequence and dies in the end. The lifetime and the end of the star depend on the mass it holds.

A massive star  turns into red super-giant and goes supernova and ends up as either a neutron star or a black-hole.

On the other hand, a small to average star like our Sun will become a red giant and throw extra mass before ending up as a white dwarf.

The color on the main sequence (blue, yellow or red) depends on the temperature and age of the star. A young hot star is blue main sequence star. On the other hand, an old low temperature star towards the end of its life is a red star.

Hence, end for a star that is small to average in size is most likely to be a D. white dwarf.


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A 0.5-kg ball moving at 5 m/s strikes a wall and rebounds in the opposite direction with a speed of 2 m/s. If the impulse occurs
mart [117]

<em>Given that:</em>

                       mass of the ball (m) = 0.5 Kg ,

                    ball strikes the wall (v₁) = 5 m/s ,

rebounds in opposite direction (v₂) = 2 m/s,

                                time duration (t) = 0.01 s,

        <em> Determine the force (F) = ?</em>

We know that from Newton's II law,

                                <em>F = m. a</em>  Newtons  

                                  (velocity acting in opposite direction, so <em>a = ( (v₁ + v₂)/t</em>

                                   = m × (v₁ + v₂)/t

                                   = 0.5 × (5 + 2)/0.01

                                  = 350 N

<em>The force acting up on the ball is 350 N</em>

                                     

6 0
3 years ago
What is the force of gravity (from the Earth) on the 700kg satellite if it’s 10km above the Earths surface?
joja [24]

Answer:

The force of gravity on a 700 kg satellite if its 10 km above Earth's surface is given by

    = {\frac{(6.674\times 10^{-11}N. m^2/kg^2)(5.97\times 10^{24}kg) }{(10\times10^3)^2} = 3984378 m / s^{2}

Explanation:

The force of gravity on a 700 kg satellite if its 10 km above Earth's surface is given by

    = {\frac{(6.674\times 10^{-11}N. m^2/kg^2)(5.97\times 10^{24}kg) }{(10\times10^3)^2} = 3984378 m / s^{2}

3 0
3 years ago
Just need to confirm an answer
Citrus2011 [14]

Answer:

B

Explanation:

Remark

If, when it reaches its maximum height where the PE is the greatest, that the maximum energy is when the ball is first kicked. That would mean its starting energy is 10 Joules.

Formula

KE = 1/2 m v^2

Givens

KE = 10 J

m = 0.2 kg

v = ?

Solution

10 = 1/2 * 0.2 * v^2

10 * 2 = 0.2 * v^2

20 = 0.2 * v^2

20/0.2 = v^2

100 = v^2

v = 10 m/s

5 0
3 years ago
A bat traveling at 10m/s for 10 seconds has traveled how much distance ​
dlinn [17]

Answer:

100m

Explanation:

Speed = distance divided by time or v=d/t . By making d the subject of the formula we have d = v x t which is 10 x 10 = 100

4 0
3 years ago
An object has no speed. Which of the following correctly describes the object’s motion?
taurus [48]

Answer:

Potential Energy

Explanation:

Potential energy is the energy an object has before it starts moving.

7 0
3 years ago
Read 2 more answers
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