<em>Given that:</em>
mass of the ball (m) = 0.5 Kg ,
ball strikes the wall (v₁) = 5 m/s ,
rebounds in opposite direction (v₂) = 2 m/s,
time duration (t) = 0.01 s,
<em> Determine the force (F) = ?</em>
We know that from Newton's II law,
<em>F = m. a</em> Newtons
(velocity acting in opposite direction, so <em>a = ( (v₁ + v₂)/t</em>
= m × (v₁ + v₂)/t
= 0.5 × (5 + 2)/0.01
= 350 N
<em>The force acting up on the ball is 350 N</em>
Answer:
The force of gravity on a 700 kg satellite if its 10 km above Earth's surface is given by
= 
= 3984378 m / 
Explanation:
The force of gravity on a 700 kg satellite if its 10 km above Earth's surface is given by
= = 3984378 m /
Answer:
B
Explanation:
Remark
If, when it reaches its maximum height where the PE is the greatest, that the maximum energy is when the ball is first kicked. That would mean its starting energy is 10 Joules.
Formula
KE = 1/2 m v^2
Givens
KE = 10 J
m = 0.2 kg
v = ?
Solution
10 = 1/2 * 0.2 * v^2
10 * 2 = 0.2 * v^2
20 = 0.2 * v^2
20/0.2 = v^2
100 = v^2
v = 10 m/s
Answer:
100m
Explanation:
Speed = distance divided by time or v=d/t . By making d the subject of the formula we have d = v x t which is 10 x 10 = 100
Answer:
Potential Energy
Explanation:
Potential energy is the energy an object has before it starts moving.
