Hi there!
Assuming the track is frictionless:
Cancel out the masses and rearrange to solve for velocity:
Plug in the given height and let g = 9.8 m/s²:
Frequency measures how many waves pass a certain point in a given amount of time.
High frequency means the waves are closer together and more frequent, making for a lower wave length.
Low frequency means the waves are farther apart and less frequent, making for a higher wave length.
So the answer is frequency.
Answer: 1175 J
Explanation:
Hooke's Law states that "the strain in a solid is proportional to the applied stress within the elastic limit of that solid."
Given
Spring constant, k = 102 N/m
Extension of the hose, x = 4.8 m
from the question, x(f) = 0 and x(i) = maximum elongation = 4.8 m
Work done =
W = 1/2 k [x(i)² - x(f)²]
Since x(f) = 0, then
W = 1/2 k x(i)²
W = 1/2 * 102 * 4.8²
W = 1/2 * 102 * 23.04
W = 1/2 * 2350.08
W = 1175.04
W = 1175 J
Therefore, the hose does a work of exactly 1175 J on the balloon
Because gravitation on the Moon is 6 times lower
Using Newtons Second Law:
F = m×a
F = (0.25 kg)(-2 m/s²)
F = -0.5 N
<h2>The correct option is C</h2>
