I'm not exactly sure but I'm thinking that it's the last one. Sorry if I'm wrong
Answer:
The coefficient of static friction is 0.29
Explanation:
Given that,
Radius of the merry-go-round, r = 4.4 m
The operator turns on the ride and brings it up to its proper turning rate of one complete rotation every 7.7 s.
We need to find the least coefficient of static friction between the cat and the merry-go-round that will allow the cat to stay in place, without sliding. For this the centripetal force is balanced by the frictional force.
![\mu mg=\dfrac{mv^2}{r}](https://tex.z-dn.net/?f=%5Cmu%20mg%3D%5Cdfrac%7Bmv%5E2%7D%7Br%7D)
v is the speed of cat, ![v=\dfrac{2\pi r}{t}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B2%5Cpi%20r%7D%7Bt%7D)
![\mu=\dfrac{4\pi^2r}{gt^2}\\\\\mu=\dfrac{4\pi^2\times 4.4}{9.8\times (7.7)^2}\\\\\mu=0.29](https://tex.z-dn.net/?f=%5Cmu%3D%5Cdfrac%7B4%5Cpi%5E2r%7D%7Bgt%5E2%7D%5C%5C%5C%5C%5Cmu%3D%5Cdfrac%7B4%5Cpi%5E2%5Ctimes%204.4%7D%7B9.8%5Ctimes%20%287.7%29%5E2%7D%5C%5C%5C%5C%5Cmu%3D0.29)
So, the least coefficient of static friction between the cat and the merry-go-round is 0.29.
A nebula is gas, dust, and other things that form and form some sort of clould like thing. It also looks cool because of the colors it produces. I'm sure you could do a web search to find more about it, I don't take astronomy hahaha
The temperature of 20°C is equal to 68.0<span>°F</span>
Answer:
I think it is "A" because the wind systems are created by uneven heating of Earth's surface.It also may help form large global wind patterns.
Explanation: